Glycerol [CH2(OH)CH2(OH)CH2(OH)] is a common ingredient in pharmaceutical and personal-care products. Calculate the boiling point of a solution containing 7.75 moles of glycerol in 1895 g of water. Kb water = 0.52°C/m.

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06-07-2024
Chemistry

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Glycerol [CH2(OH)CH2(OH)CH2(OH)] is a common ingredient in pharmaceutical and personal-care products. Calculate the boiling point of a solution containing 7.75 moles of glycerol in 1895 g of water. Kb water = 0.52°C/m.

Sagot :

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Glycerol [CH2(OH)CH2(OH)CH2(OH)] is a common ingredient in pharmaceutical and personal-care products. Calculate the boiling point of a solution containing 7.75 moles of glycerol in 1895 g of water. Kb water = 0.52°C/m.

Sagot :

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