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Find the slope-intercept equation of the line that has the given characteristics:

Slope: [tex]\(-\frac{11}{7}\)[/tex]

y-intercept: [tex]\((0,-4)\)[/tex]

The slope-intercept equation is [tex]\(\square\)[/tex]

(Type an equation. Type your answer in slope-intercept form. Use integers or fractions for any numbers in the equation.)

Sagot :

GinnyAnswer
To find the slope-intercept equation of a line, we use the slope-intercept form of a linear equation:
[tex]\[ y = mx + b \][/tex]
where [tex]\( m \)[/tex] represents the slope of the line and [tex]\( b \)[/tex] represents the y-intercept.

Given the slope [tex]\( m = -\frac{11}{7} \)[/tex] and the y-intercept [tex]\( b = -4 \)[/tex], we substitute these values into the slope-intercept form equation.

So, substituting [tex]\( m \)[/tex] and [tex]\( b \)[/tex] into the equation, we get:
[tex]\[ y = \left(-\frac{11}{7}\right)x + (-4) \][/tex]

Simplifying the equation, we have:
[tex]\[ y = -\frac{11}{7}x - 4 \][/tex]

Therefore, the slope-intercept equation of the line is:
[tex]\[ y = -\frac{11}{7}x - 4 \][/tex]
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