Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Discover precise answers to your questions from a wide range of experts on our user-friendly Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
To determine whether each set of quantum numbers describes a valid orbital, we must check the following conditions for the principal quantum number [tex]\(n\)[/tex], angular momentum quantum number [tex]\(l\)[/tex], and magnetic quantum number [tex]\(m\)[/tex]:
1. [tex]\(n > 0\)[/tex]
2. [tex]\(0 \leq l < n\)[/tex]
3. [tex]\(-l \leq m \leq l\)[/tex]
Let's evaluate each set of quantum numbers one by one:
1. Set [tex]\( (n=1, l=0, m=0) \)[/tex]:
- [tex]\( n = 1 \)[/tex]: [tex]\(n > 0\)[/tex], so this is valid.
- [tex]\( l = 0 \)[/tex]: [tex]\(0 \leq l < n\)[/tex], so this is valid.
- [tex]\( m = 0 \)[/tex]: [tex]\(-l \leq m \leq l\)[/tex], so this is valid.
- Conclusion: This is a valid set of quantum numbers.
2. Set [tex]\( (n=2, l=1, m=3) \)[/tex]:
- [tex]\( n = 2 \)[/tex]: [tex]\(n > 0\)[/tex], so this is valid.
- [tex]\( l = 1 \)[/tex]: [tex]\(0 \leq l < n\)[/tex], so this is valid.
- [tex]\( m = 3 \)[/tex]: [tex]\(-l \leq m \leq l\)[/tex], [tex]\(-1 \leq 3 \leq 1\)[/tex] is not satisfied.
- Conclusion: This is not a valid set of quantum numbers.
3. Set [tex]\( (n=2, l=2, m=2) \)[/tex]:
- [tex]\( n = 2 \)[/tex]: [tex]\(n > 0\)[/tex], so this is valid.
- [tex]\( l = 2 \)[/tex]: [tex]\(0 \leq l < n\)[/tex], [tex]\(0 \leq 2 < 2\)[/tex] is not satisfied.
- [tex]\( m = 2 \)[/tex]: This does not need to be checked further since [tex]\(l\)[/tex] is not valid.
- Conclusion: This is not a valid set of quantum numbers.
4. Set [tex]\( (n=3, l=0, m=0) \)[/tex]:
- [tex]\( n = 3 \)[/tex]: [tex]\(n > 0\)[/tex], so this is valid.
- [tex]\( l = 0 \)[/tex]: [tex]\(0 \leq l < n\)[/tex], so this is valid.
- [tex]\( m = 0 \)[/tex]: [tex]\(-l \leq m \leq l\)[/tex], so this is valid.
- Conclusion: This is a valid set of quantum numbers.
5. Set [tex]\( (n=5, l=4, m=-3) \)[/tex]:
- [tex]\( n = 5 \)[/tex]: [tex]\(n > 0\)[/tex], so this is valid.
- [tex]\( l = 4 \)[/tex]: [tex]\(0 \leq l < n\)[/tex], so this is valid.
- [tex]\( m = -3 \)[/tex]: [tex]\(-l \leq m \leq l\)[/tex], [tex]\(-4 \leq -3 \leq 4\)[/tex] is satisfied.
- Conclusion: This is a valid set of quantum numbers.
6. Set [tex]\( (n=4, l=-2, m=2) \)[/tex]:
- [tex]\( n = 4 \)[/tex]: [tex]\(n > 0\)[/tex], so this is valid.
- [tex]\( l = -2 \)[/tex]: [tex]\(0 \leq l < n\)[/tex], [tex]\(0 \leq -2 < 4\)[/tex] is not satisfied.
- [tex]\( m = 2 \)[/tex]: This does not need to be checked further since [tex]\(l\)[/tex] is not valid.
- Conclusion: This is not a valid set of quantum numbers.
Final Conclusion: The sets of quantum numbers that describe valid orbitals are:
- [tex]\( (n=1, l=0, m=0) \)[/tex]
- [tex]\( (n=3, l=0, m=0) \)[/tex]
- [tex]\( (n=5, l=4, m=-3) \)[/tex]
1. [tex]\(n > 0\)[/tex]
2. [tex]\(0 \leq l < n\)[/tex]
3. [tex]\(-l \leq m \leq l\)[/tex]
Let's evaluate each set of quantum numbers one by one:
1. Set [tex]\( (n=1, l=0, m=0) \)[/tex]:
- [tex]\( n = 1 \)[/tex]: [tex]\(n > 0\)[/tex], so this is valid.
- [tex]\( l = 0 \)[/tex]: [tex]\(0 \leq l < n\)[/tex], so this is valid.
- [tex]\( m = 0 \)[/tex]: [tex]\(-l \leq m \leq l\)[/tex], so this is valid.
- Conclusion: This is a valid set of quantum numbers.
2. Set [tex]\( (n=2, l=1, m=3) \)[/tex]:
- [tex]\( n = 2 \)[/tex]: [tex]\(n > 0\)[/tex], so this is valid.
- [tex]\( l = 1 \)[/tex]: [tex]\(0 \leq l < n\)[/tex], so this is valid.
- [tex]\( m = 3 \)[/tex]: [tex]\(-l \leq m \leq l\)[/tex], [tex]\(-1 \leq 3 \leq 1\)[/tex] is not satisfied.
- Conclusion: This is not a valid set of quantum numbers.
3. Set [tex]\( (n=2, l=2, m=2) \)[/tex]:
- [tex]\( n = 2 \)[/tex]: [tex]\(n > 0\)[/tex], so this is valid.
- [tex]\( l = 2 \)[/tex]: [tex]\(0 \leq l < n\)[/tex], [tex]\(0 \leq 2 < 2\)[/tex] is not satisfied.
- [tex]\( m = 2 \)[/tex]: This does not need to be checked further since [tex]\(l\)[/tex] is not valid.
- Conclusion: This is not a valid set of quantum numbers.
4. Set [tex]\( (n=3, l=0, m=0) \)[/tex]:
- [tex]\( n = 3 \)[/tex]: [tex]\(n > 0\)[/tex], so this is valid.
- [tex]\( l = 0 \)[/tex]: [tex]\(0 \leq l < n\)[/tex], so this is valid.
- [tex]\( m = 0 \)[/tex]: [tex]\(-l \leq m \leq l\)[/tex], so this is valid.
- Conclusion: This is a valid set of quantum numbers.
5. Set [tex]\( (n=5, l=4, m=-3) \)[/tex]:
- [tex]\( n = 5 \)[/tex]: [tex]\(n > 0\)[/tex], so this is valid.
- [tex]\( l = 4 \)[/tex]: [tex]\(0 \leq l < n\)[/tex], so this is valid.
- [tex]\( m = -3 \)[/tex]: [tex]\(-l \leq m \leq l\)[/tex], [tex]\(-4 \leq -3 \leq 4\)[/tex] is satisfied.
- Conclusion: This is a valid set of quantum numbers.
6. Set [tex]\( (n=4, l=-2, m=2) \)[/tex]:
- [tex]\( n = 4 \)[/tex]: [tex]\(n > 0\)[/tex], so this is valid.
- [tex]\( l = -2 \)[/tex]: [tex]\(0 \leq l < n\)[/tex], [tex]\(0 \leq -2 < 4\)[/tex] is not satisfied.
- [tex]\( m = 2 \)[/tex]: This does not need to be checked further since [tex]\(l\)[/tex] is not valid.
- Conclusion: This is not a valid set of quantum numbers.
Final Conclusion: The sets of quantum numbers that describe valid orbitals are:
- [tex]\( (n=1, l=0, m=0) \)[/tex]
- [tex]\( (n=3, l=0, m=0) \)[/tex]
- [tex]\( (n=5, l=4, m=-3) \)[/tex]
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.