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Find F1 and F3, then calculate the net force on q2.
+8.0 x 10 C
+91
0.10 m-
+3.5 x 106 C
+92
F₁ = 25.2 N
F3 = [?] N
0.15 m-
-2.5 x 106 C
93
F² =
N
F3 is the force exerted onto q2 by q3.
Forces directed left are negative (-); right are positive (+).
newtons (N)
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Sagot :

Qlover1

Answer:

F3 is the applied force acting on charge q1, and its magnitude is 42 N. The net force acting on charge q2 is 17.2 N.

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