Discover the answers you need at Westonci.ca, where experts provide clear and concise information on various topics. Discover solutions to your questions from experienced professionals across multiple fields on our comprehensive Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
Let's solve this problem step-by-step:
1. Define Variables:
- Let the original number of students be [tex]\( n \)[/tex].
- The total budget for the food is Rs. 7200.
- The cost per student initially would be [tex]\( \frac{7200}{n} \)[/tex].
- When four students couldn't join, the number of students became [tex]\( n - 4 \)[/tex].
- The new cost per student after the reduction in number of students increased by Rs. 60, so it became [tex]\( \frac{7200}{n - 4} \)[/tex].
2. Create an equation reflecting the change in the cost per student:
- According to the problem, the new cost per student is the previous cost plus Rs. 60.
[tex]\[ \frac{7200}{n - 4} = \frac{7200}{n} + 60 \][/tex]
3. Solve the equation for [tex]\( n \)[/tex]:
- Rearrange the equation to:
[tex]\[ \frac{7200}{n - 4} - \frac{7200}{n} = 60 \][/tex]
- Find a common denominator and combine the terms on the left-hand side:
[tex]\[ \frac{7200n - 7200(n - 4)}{n(n - 4)} = 60 \][/tex]
- Simplify the numerator:
[tex]\[ \frac{7200n - 7200n + 28800}{n(n - 4)} = 60 \][/tex]
[tex]\[ \frac{28800}{n(n - 4)} = 60 \][/tex]
- Multiply both sides by [tex]\( n(n - 4) \)[/tex] to get rid of the denominator:
[tex]\[ 28800 = 60n(n - 4) \][/tex]
- Simplify:
[tex]\[ 28800 = 60(n^2 - 4n) \][/tex]
[tex]\[ 480 = n^2 - 4n \][/tex]
[tex]\[ n^2 - 4n - 480 = 0 \][/tex]
4. Solve the quadratic equation:
- Use the quadratic formula [tex]\( n = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)[/tex] where [tex]\( a = 1 \)[/tex], [tex]\( b = -4 \)[/tex], and [tex]\( c = -480 \)[/tex]:
[tex]\[ n = \frac{4 \pm \sqrt{16 + 1920}}{2} \][/tex]
[tex]\[ n = \frac{4 \pm \sqrt{1936}}{2} \][/tex]
[tex]\[ n = \frac{4 \pm 44}{2} \][/tex]
- This gives us two solutions:
[tex]\[ n = \frac{48}{2} = 24 \quad \text{(positive solution)} \][/tex]
[tex]\[ n = \frac{-40}{2} = -20 \quad \text{(negative, so we discard this)} \][/tex]
5. Determine the number of students who went for the picnic:
- The original number of students is 24.
- Since 4 students couldn't join, the number of students who went for the picnic is:
[tex]\[ 24 - 4 = 20 \][/tex]
Conclusion:
The original number of students planned for the picnic was 24, but since 4 students couldn’t join, the number of students who went for the picnic is 20.
1. Define Variables:
- Let the original number of students be [tex]\( n \)[/tex].
- The total budget for the food is Rs. 7200.
- The cost per student initially would be [tex]\( \frac{7200}{n} \)[/tex].
- When four students couldn't join, the number of students became [tex]\( n - 4 \)[/tex].
- The new cost per student after the reduction in number of students increased by Rs. 60, so it became [tex]\( \frac{7200}{n - 4} \)[/tex].
2. Create an equation reflecting the change in the cost per student:
- According to the problem, the new cost per student is the previous cost plus Rs. 60.
[tex]\[ \frac{7200}{n - 4} = \frac{7200}{n} + 60 \][/tex]
3. Solve the equation for [tex]\( n \)[/tex]:
- Rearrange the equation to:
[tex]\[ \frac{7200}{n - 4} - \frac{7200}{n} = 60 \][/tex]
- Find a common denominator and combine the terms on the left-hand side:
[tex]\[ \frac{7200n - 7200(n - 4)}{n(n - 4)} = 60 \][/tex]
- Simplify the numerator:
[tex]\[ \frac{7200n - 7200n + 28800}{n(n - 4)} = 60 \][/tex]
[tex]\[ \frac{28800}{n(n - 4)} = 60 \][/tex]
- Multiply both sides by [tex]\( n(n - 4) \)[/tex] to get rid of the denominator:
[tex]\[ 28800 = 60n(n - 4) \][/tex]
- Simplify:
[tex]\[ 28800 = 60(n^2 - 4n) \][/tex]
[tex]\[ 480 = n^2 - 4n \][/tex]
[tex]\[ n^2 - 4n - 480 = 0 \][/tex]
4. Solve the quadratic equation:
- Use the quadratic formula [tex]\( n = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)[/tex] where [tex]\( a = 1 \)[/tex], [tex]\( b = -4 \)[/tex], and [tex]\( c = -480 \)[/tex]:
[tex]\[ n = \frac{4 \pm \sqrt{16 + 1920}}{2} \][/tex]
[tex]\[ n = \frac{4 \pm \sqrt{1936}}{2} \][/tex]
[tex]\[ n = \frac{4 \pm 44}{2} \][/tex]
- This gives us two solutions:
[tex]\[ n = \frac{48}{2} = 24 \quad \text{(positive solution)} \][/tex]
[tex]\[ n = \frac{-40}{2} = -20 \quad \text{(negative, so we discard this)} \][/tex]
5. Determine the number of students who went for the picnic:
- The original number of students is 24.
- Since 4 students couldn't join, the number of students who went for the picnic is:
[tex]\[ 24 - 4 = 20 \][/tex]
Conclusion:
The original number of students planned for the picnic was 24, but since 4 students couldn’t join, the number of students who went for the picnic is 20.
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.