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Sagot :
Certainly, let's solve the problem step-by-step.
1. How much did the bicycle cost?
The given equation for the amount of money Hugo owes is:
[tex]\[y - 10 = -2(x - 10)\][/tex]
To find the initial cost of the bicycle, we need to determine the amount Hugo owed initially (week 0). This means we set [tex]\( x = 0 \)[/tex] because that represents the start before any payments were made.
Substitute [tex]\( x = 0 \)[/tex] into the equation:
[tex]\[ y - 10 = -2(0 - 10) \][/tex]
[tex]\[ y - 10 = -2(-10) \][/tex]
[tex]\[ y - 10 = 20 \][/tex]
[tex]\[ y = 20 + 10 \][/tex]
[tex]\[ y = 30 \][/tex]
So, the initial cost of the bicycle was \[tex]$30. 2. After how many weeks will Hugo finish paying for the bike? Hugo will have finished paying for the bike when the amount of money he owes (\( y \)) is equal to 0. Set \( y = 0 \) in the given equation and solve for \( x \): \[ 0 - 10 = -2(x - 10) \] \[ -10 = -2(x - 10) \] Divide both sides by -2: \[ 5 = x - 10 \] \[ x = 5 + 10 \] \[ x = 15 \] So, Hugo will finish paying for the bike after 15 weeks. 3. Create the Graph To graph the equation \( y - 10 = -2(x - 10) \), we can determine a few points to plot. \[ \begin{array}{|c|c|} \hline x & y \\ \hline 5 & 20 \\ \hline 10 & 10 \\ \hline 15 & 0 \\ \hline \end{array} \] - At \( x = 5 \): \[ y - 10 = -2(5 - 10) \] \[ y - 10 = 10 \] \[ y = 20 \] - At \( x = 10 \): \[ y - 10 = -2(10 - 10) \] \[ y - 10 = 0 \] \[ y = 10 \] - At \( x = 15 \): \[ y - 10 = -2(15 - 10) \] \[ y - 10 = -10 \] \[ y = 0 \] These points (\(x, y\)) are (5, 20), (10, 10), and (15, 0). You can plot these points on a graph, and draw a line through them to visualize how the amount Hugo owes decreases over time. Conclusion: - The cost of the bicycle is \$[/tex]30.
- Hugo will finish paying for the bike in 15 weeks.
Here’s the table for the graph:
[tex]\[ \begin{array}{|c|c|} \hline x & y \\ \hline 5 & 20 \\ \hline 10 & 10 \\ \hline 15 & 0 \\ \hline \end{array} \][/tex]
1. How much did the bicycle cost?
The given equation for the amount of money Hugo owes is:
[tex]\[y - 10 = -2(x - 10)\][/tex]
To find the initial cost of the bicycle, we need to determine the amount Hugo owed initially (week 0). This means we set [tex]\( x = 0 \)[/tex] because that represents the start before any payments were made.
Substitute [tex]\( x = 0 \)[/tex] into the equation:
[tex]\[ y - 10 = -2(0 - 10) \][/tex]
[tex]\[ y - 10 = -2(-10) \][/tex]
[tex]\[ y - 10 = 20 \][/tex]
[tex]\[ y = 20 + 10 \][/tex]
[tex]\[ y = 30 \][/tex]
So, the initial cost of the bicycle was \[tex]$30. 2. After how many weeks will Hugo finish paying for the bike? Hugo will have finished paying for the bike when the amount of money he owes (\( y \)) is equal to 0. Set \( y = 0 \) in the given equation and solve for \( x \): \[ 0 - 10 = -2(x - 10) \] \[ -10 = -2(x - 10) \] Divide both sides by -2: \[ 5 = x - 10 \] \[ x = 5 + 10 \] \[ x = 15 \] So, Hugo will finish paying for the bike after 15 weeks. 3. Create the Graph To graph the equation \( y - 10 = -2(x - 10) \), we can determine a few points to plot. \[ \begin{array}{|c|c|} \hline x & y \\ \hline 5 & 20 \\ \hline 10 & 10 \\ \hline 15 & 0 \\ \hline \end{array} \] - At \( x = 5 \): \[ y - 10 = -2(5 - 10) \] \[ y - 10 = 10 \] \[ y = 20 \] - At \( x = 10 \): \[ y - 10 = -2(10 - 10) \] \[ y - 10 = 0 \] \[ y = 10 \] - At \( x = 15 \): \[ y - 10 = -2(15 - 10) \] \[ y - 10 = -10 \] \[ y = 0 \] These points (\(x, y\)) are (5, 20), (10, 10), and (15, 0). You can plot these points on a graph, and draw a line through them to visualize how the amount Hugo owes decreases over time. Conclusion: - The cost of the bicycle is \$[/tex]30.
- Hugo will finish paying for the bike in 15 weeks.
Here’s the table for the graph:
[tex]\[ \begin{array}{|c|c|} \hline x & y \\ \hline 5 & 20 \\ \hline 10 & 10 \\ \hline 15 & 0 \\ \hline \end{array} \][/tex]
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