Answered

Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Get the answers you need quickly and accurately from a dedicated community of experts on our Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

10. खण्डीकरण गर्नुस् (Factorize)
[tex]\[ y^2 - xy + x - y \][/tex]

11. \text{विएएकी बीजीय अभिव्यक्तिहरूमा साधा लगाउनुहोस्} (Find a common factor in the given algebraic expressions):
[tex]\[ m(x-y), \ n(y-x) \][/tex]

Sagot :

GinnyAnswer
Factorizing [tex]\( y^2 - xy + x - y \)[/tex]:

Step 1: Group the terms in pairs that have common factors.
[tex]\[ (y^2 - xy) + (x - y) \][/tex]

Step 2: Factor out the common factor from each pair.
[tex]\[ y(y - x) + 1(x - y) \][/tex]

Notice that [tex]\( (x - y) \)[/tex] can be seen as [tex]\(-(y - x)\)[/tex]:
[tex]\[ y(y - x) - 1(y - x) \][/tex]

Step 3: Factor out the common factor [tex]\( (y - x) \)[/tex]:
[tex]\[ (y - x)(y - 1) \][/tex]

Step 4: Simplify, keeping in mind that the negative sign distributes:
[tex]\[ - (x - y)(y - 1) \][/tex]

Therefore, the factorized form of the expression [tex]\( y^2 - xy + x - y \)[/tex] is:
[tex]\[ -(x - y)(y - 1) \][/tex]
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.