Answered

At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Get accurate and detailed answers to your questions from a dedicated community of experts on our Q&A platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

10. खण्डीकरण गर्नुस् (Factorize)
[tex]\[ y^2 - xy + x - y \][/tex]

11. \text{विएएकी बीजीय अभिव्यक्तिहरूमा साधा लगाउनुहोस्} (Find a common factor in the given algebraic expressions):
[tex]\[ m(x-y), \ n(y-x) \][/tex]

Sagot :

GinnyAnswer
Factorizing [tex]\( y^2 - xy + x - y \)[/tex]:

Step 1: Group the terms in pairs that have common factors.
[tex]\[ (y^2 - xy) + (x - y) \][/tex]

Step 2: Factor out the common factor from each pair.
[tex]\[ y(y - x) + 1(x - y) \][/tex]

Notice that [tex]\( (x - y) \)[/tex] can be seen as [tex]\(-(y - x)\)[/tex]:
[tex]\[ y(y - x) - 1(y - x) \][/tex]

Step 3: Factor out the common factor [tex]\( (y - x) \)[/tex]:
[tex]\[ (y - x)(y - 1) \][/tex]

Step 4: Simplify, keeping in mind that the negative sign distributes:
[tex]\[ - (x - y)(y - 1) \][/tex]

Therefore, the factorized form of the expression [tex]\( y^2 - xy + x - y \)[/tex] is:
[tex]\[ -(x - y)(y - 1) \][/tex]
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.