aryanmandal426
Answered

Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Our platform provides a seamless experience for finding reliable answers from a knowledgeable network of professionals. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

121.20OmL of an aqueous solution of a protein contains its 1.26 g The osmotic pressure of this solution at300 K is found to be 2.57 x 10-3 bar. The molar mass of prote in will be (R=0.083Lbarmol-lk-l) (a)S1022gmol (b)122044gmol- (c)3 101lg mol (d)61038g mol​

Sagot :

ibraahimmuqtar16

Answer:

Given data:

Volume of solution, V = 121.20 mL = 0.1212 L

Mass of protein, m = 1.26 g

Osmotic pressure, π = 2.57 x 10^-3 bar

Temperature, T = 300 K

Universal gas constant, R = 0.083 L bar mol^-1 K^-1

We can use the formula for osmotic pressure: π = (n/V)RT, where n is the number of moles of solute.

First, we need to calculate the number of moles of protein: n = m / M, where M is the molar mass of the protein.

Next, we can rearrange the formula for osmotic pressure to solve for the molar mass, M: M=m/n

Substitute the values into the equations: n = 1.26 g / M π = (n / V)RT

Now, rearrange the osmotic pressure formula to solve for M: M = m / (πV/RT)

Substitute the given values into the equation and solve for M: M=1.26 g/((2.57 x 10^-3 bar)* 0.1212 L/ (0.083 L bar mol^-1 K^-1* 300 K))

Calculating the value of M will give the molar mass of the protein in grams per mole.

Therefore, the molar mass of the protein will be calculated to

determine which option it matches with:

(a) 51022 g/mol

(b) 122044 g/mol

(c) 31011 g/mol

(d) 61038 g/mol

Please calculate the final answer accordingly.

We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.