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the equation of a straight line is 5y=-3x +1 what is the gradient of the line?

Sagot :

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Answer:

To find the gradient of a straight line given by the equation \(5y = -3x + 1\), we need to rewrite the equation in the slope-intercept form, which is \(y = mx + c\), where \(m\) is the gradient (slope) of the line.

1. First, rearrange the given equation to the slope-intercept form:

5y = -3x+1

y=-x+0.5

2. Now, compare the equation with the slope-intercept form \(y mx + c\), we can see that the coefficient of \(x\) is the gradient of the line.

3. Therefore, the gradient of the line given by the equation \(5y = -3x + 1\) is \(-\frac{3}{5}\).

So, the gradient of the line is - 3.

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