Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Discover a wealth of knowledge from professionals across various disciplines on our user-friendly Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

Simplify the following expression:

[tex]\[ \frac{(2.5)^2 + 2 \times 2.5 \times 1.4 + (1.4)^2}{2.5 + 1.4} \][/tex]


Sagot :

Let's break down the given expression and solve it step-by-step:

[tex]\[ \frac{(2.5)^2 + 2 \times 2.5 \times 1.4 + (1.4)^2}{2.5 + 1.4} \][/tex]

### Step 1: Calculate [tex]\((2.5)^2\)[/tex]
First, we need to square 2.5:
[tex]\[ (2.5)^2 = 2.5 \times 2.5 = 6.25 \][/tex]

### Step 2: Calculate [tex]\(2 \times 2.5 \times 1.4\)[/tex]
Next, we calculate the product of 2, 2.5, and 1.4:
[tex]\[ 2 \times 2.5 \times 1.4 = 2 \times 3.5 = 7.0 \][/tex]

### Step 3: Calculate [tex]\((1.4)^2\)[/tex]
Then, we square 1.4:
[tex]\[ (1.4)^2 = 1.4 \times 1.4 = 1.96 \][/tex]

### Step 4: Sum up the results from steps 1, 2, and 3 for the numerator
Now, we add together the results from steps 1, 2, and 3 to get the numerator:
[tex]\[ 6.25 + 7.0 + 1.96 = 15.21 \][/tex]

### Step 5: Calculate the denominator
Next, we add 2.5 and 1.4 for the denominator:
[tex]\[ 2.5 + 1.4 = 3.9 \][/tex]

### Step 6: Divide the numerator by the denominator
Finally, we divide the numerator by the denominator to find the result:
[tex]\[ \frac{15.21}{3.9} = 3.9 \][/tex]

### Summary:
The detailed step-by-step solution gives us:
- Numerator: [tex]\(15.21\)[/tex]
- Denominator: [tex]\(3.9\)[/tex]
- Result: [tex]\(3.9\)[/tex]

So, the value of the expression is [tex]\(3.9\)[/tex].
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.