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Sagot :
To determine the magnification of the real image, we can use the given formula for magnification:
[tex]\[ m = -\frac{d_i}{d_o} \][/tex]
Here, [tex]\( d_i \)[/tex] is the image distance, and [tex]\( d_o \)[/tex] is the object distance. In this problem:
- The image distance [tex]\( d_i \)[/tex] is [tex]\( 50.0 \)[/tex] cm.
- The object distance [tex]\( d_o \)[/tex] is [tex]\( 10.0 \)[/tex] cm.
Now, let's plug these values into the magnification formula:
1. Identify the values:
[tex]\[ d_i = 50.0 \, \text{cm} \][/tex]
[tex]\[ d_o = 10.0 \, \text{cm} \][/tex]
2. Substitute the values into the formula:
[tex]\[ m = -\frac{50.0}{10.0} \][/tex]
3. Perform the division:
[tex]\[ m = -5.0 \][/tex]
Therefore, the magnification of the image is [tex]\(-5.0\)[/tex].
So, the correct answer is:
D. [tex]\(-5.0\)[/tex]
[tex]\[ m = -\frac{d_i}{d_o} \][/tex]
Here, [tex]\( d_i \)[/tex] is the image distance, and [tex]\( d_o \)[/tex] is the object distance. In this problem:
- The image distance [tex]\( d_i \)[/tex] is [tex]\( 50.0 \)[/tex] cm.
- The object distance [tex]\( d_o \)[/tex] is [tex]\( 10.0 \)[/tex] cm.
Now, let's plug these values into the magnification formula:
1. Identify the values:
[tex]\[ d_i = 50.0 \, \text{cm} \][/tex]
[tex]\[ d_o = 10.0 \, \text{cm} \][/tex]
2. Substitute the values into the formula:
[tex]\[ m = -\frac{50.0}{10.0} \][/tex]
3. Perform the division:
[tex]\[ m = -5.0 \][/tex]
Therefore, the magnification of the image is [tex]\(-5.0\)[/tex].
So, the correct answer is:
D. [tex]\(-5.0\)[/tex]
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