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A circuit has a voltage drop of [tex]$12.0 V$[/tex] across a [tex]$60.0 \Omega$[/tex] resistor that carries a current of [tex][tex]$0.200 A$[/tex][/tex]. What is the power conducted by the resistor? Use [tex]P = V I[/tex].

A. [tex]720.0 W[/tex]
B. [tex]2.40 W[/tex]
C. [tex]5.00 W[/tex]
D. [tex]12.0 W[/tex]

Sagot :

GinnyAnswer
To determine the power conducted by the resistor, we use the formula for electric power:

[tex]\[ P = V \times I \][/tex]

Where:
- [tex]\( P \)[/tex] is the power in watts (W)
- [tex]\( V \)[/tex] is the voltage in volts (V)
- [tex]\( I \)[/tex] is the current in amperes (A)

Given the following values:
- Voltage [tex]\( V = 12.0 \)[/tex] volts
- Current [tex]\( I = 0.200 \)[/tex] amperes

We substitute these values into the power formula:

[tex]\[ P = 12.0 \, \text{V} \times 0.200 \, \text{A} \][/tex]

Performing the multiplication:

[tex]\[ P = 2.4000000000000004 \, \text{W} \][/tex]

Therefore, the power conducted by the resistor is:

[tex]\[ 2.4 \, \text{W} \][/tex]

From the provided options, the correct answer is:

B. [tex]\( 2.40 \, \text{W} \)[/tex]
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