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Diana is trying to pay off a loan. She borrowed
$
700
$700​ and plans on making monthly payments of
$
70
$70​. Using this information, create an equation written in slope-intercept form that models the amount owed

y​ of Diana’s loan after

x​ months.


Sagot :

To create an equation in slope-intercept form that models the amount owed

y after

x months for Diana's loan, we start with the following information:

Diana borrowed

$

700

$700.

She plans to make monthly payments of

$

70

$70.

The amount owed

y after

x months can be represented as follows:

Initial amount borrowed:

=

700

y=700

Amount paid off per month:

Diana pays

$

70

$70 per month.

Therefore, the amount the loan decreases each month is

$

70

$70.

Equation in slope-intercept form:

After

x months, the amount owed

y is reduced by

70

70x (since she pays off

$

70

$70 each month). Therefore, the equation can be written as:

=

700

70

y=700−70x

Interpretation of the equation:

y represents the amount of the loan still owed after

x months.

700

700 is the initial amount borrowed.

70

−70x accounts for the reduction in the loan amount due to the monthly payments of

$

70

$70.

Slope-intercept form:

The equation

=

700

70

y=700−70x is in slope-intercept form, where:

The slope

m is

70

−70, indicating that the amount owed decreases by

$

70

$70 per month.

The y-intercept

b is

700

700, which is the initial amount borrowed.

Therefore, the equation in slope-intercept form that models the amount owed

y of Diana’s loan after

x months is:

=

700

70

y=700−70x