Westonci.ca connects you with experts who provide insightful answers to your questions. Join us today and start learning! Discover a wealth of knowledge from professionals across various disciplines on our user-friendly Q&A platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
To create an equation in slope-intercept form that models the amount owed
y after
x months for Diana's loan, we start with the following information:
Diana borrowed
$
700
$700.
She plans to make monthly payments of
$
70
$70.
The amount owed
y after
x months can be represented as follows:
Initial amount borrowed:
=
700
y=700
Amount paid off per month:
Diana pays
$
70
$70 per month.
Therefore, the amount the loan decreases each month is
$
70
$70.
Equation in slope-intercept form:
After
x months, the amount owed
y is reduced by
70
70x (since she pays off
$
70
$70 each month). Therefore, the equation can be written as:
=
700
−
70
y=700−70x
Interpretation of the equation:
y represents the amount of the loan still owed after
x months.
700
700 is the initial amount borrowed.
−
70
−70x accounts for the reduction in the loan amount due to the monthly payments of
$
70
$70.
Slope-intercept form:
The equation
=
700
−
70
y=700−70x is in slope-intercept form, where:
The slope
m is
−
70
−70, indicating that the amount owed decreases by
$
70
$70 per month.
The y-intercept
b is
700
700, which is the initial amount borrowed.
Therefore, the equation in slope-intercept form that models the amount owed
y of Diana’s loan after
x months is:
=
700
−
70
y=700−70x
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.
