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B. Aplica tus conocimientos en el desarrollo de los siguientes ejercicios.

1. Calcula mentalmente y completa:
a) [tex]$\frac{1}{4}$[/tex] de [tex]$32 =$[/tex] [tex]$\square$[/tex]
b) [tex]$\frac{3}{4}$[/tex] de [tex]$24 =$[/tex] [tex]$\square$[/tex]
c) [tex]$\frac{1}{2}$[/tex] de [tex]$52 =$[/tex] [tex]$\square$[/tex]
d) [tex]$\frac{2}{5}$[/tex] de [tex]$20 =$[/tex] [tex]$\square$[/tex]
e) [tex]$\frac{5}{6}$[/tex] de [tex]$30 =$[/tex] [tex]$\square$[/tex]
f) [tex]$\frac{2}{7}$[/tex] de [tex]$7 =$[/tex] [tex]$\square$[/tex]
g) [tex]$\frac{3}{4}$[/tex] de [tex]$12 =$[/tex] [tex]$\square$[/tex]
h) [tex]$\frac{5}{8}$[/tex] de [tex]$40 =$[/tex] [tex]$\square$[/tex]

Sagot :

Claro, a continuación te explico paso a paso cómo resolver cada uno de los ejercicios:

1. Calcula mentalmente y completa

a) [tex]\(\frac{1}{4}\)[/tex] de [tex]\(32\)[/tex]:
Primero, encontramos la cuarta parte de 32:
[tex]\[\frac{1}{4} \times 32 = 8.0\][/tex]

b) [tex]\(\frac{3}{4}\)[/tex] de [tex]\(24\)[/tex]:
Ahora, multiplicamos 24 por tres cuartos:
[tex]\[\frac{3}{4} \times 24 = 18.0\][/tex]

c) [tex]\(\frac{1}{2}\)[/tex] de [tex]\(52\)[/tex]:
Para encontrar la mitad de 52:
[tex]\[\frac{1}{2} \times 52 = 26.0\][/tex]

d) [tex]\(\frac{2}{5}\)[/tex] de [tex]\(20\)[/tex]:
Ahora, buscamos dos quintos de 20:
[tex]\[\frac{2}{5} \times 20 = 8.0\][/tex]

e) [tex]\(\frac{5}{6}\)[/tex] de [tex]\(30\)[/tex]:
Calculamos cinco sextos de 30:
[tex]\[\frac{5}{6} \times 30 = 25.0\][/tex]

f) [tex]\(\frac{2}{7}\)[/tex] de [tex]\(0\)[/tex]:
Cualquier número multiplicado por 0 es 0:
[tex]\[\frac{2}{7} \times 0 = 0.0\][/tex]

g) [tex]\(3\)[/tex] de [tex]\(-1\)[/tex]:
Multiplicamos 3 por -1:
[tex]\[3 \times (-1) = -3\][/tex]

h) [tex]\(\frac{5}{8}\)[/tex] de [tex]\(40\)[/tex]:
Finalmente, encontramos cinco octavos de 40:
[tex]\[\frac{5}{8} \times 40 = 25.0\][/tex]

Entonces, las respuestas son:

a) [tex]\(8.0\)[/tex]
b) [tex]\(18.0\)[/tex]
c) [tex]\(26.0\)[/tex]
d) [tex]\(8.0\)[/tex]
e) [tex]\(25.0\)[/tex]
f) [tex]\(0.0\)[/tex]
g) [tex]\(-3\)[/tex]
h) [tex]\(25.0\)[/tex]
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