At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Get detailed answers to your questions from a community of experts dedicated to providing accurate information. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
Certainly! Let's solve the problem step-by-step based on the given information.
### Step-by-Step Solution:
#### Part a: Calculating the sides and [tex]\( S \)[/tex]
1. Understanding the ratio:
The sides of the triangle are in the ratio 6:9:10. Let's denote the sides as [tex]\( 6x \)[/tex], [tex]\( 9x \)[/tex], and [tex]\( 10x \)[/tex], where [tex]\( x \)[/tex] is a common multiplier.
2. Given perimeter:
The perimeter of the triangle is [tex]\( 2500 \, \text{m} \)[/tex].
Thus, we have:
[tex]\[ 6x + 9x + 10x = 2500 \][/tex]
3. Solving for [tex]\( x \)[/tex]:
Combine the terms on the left-hand side:
[tex]\[ 25x = 2500 \][/tex]
Divide both sides by 25:
[tex]\[ x = \frac{2500}{25} = 100 \][/tex]
4. Calculating the sides:
Using [tex]\( x = 100 \)[/tex]:
[tex]\[ a = 6x = 6 \times 100 = 600 \, \text{m} \][/tex]
[tex]\[ b = 9x = 9 \times 100 = 900 \, \text{m} \][/tex]
[tex]\[ c = 10x = 10 \times 100 = 1000 \, \text{m} \][/tex]
5. Calculating the semi-perimeter [tex]\( S \)[/tex]:
The semi-perimeter [tex]\( S \)[/tex] is half of the perimeter:
[tex]\[ S = \frac{\text{Perimeter}}{2} = \frac{2500}{2} = 1250 \, \text{m} \][/tex]
Therefore, the value of [tex]\( S \)[/tex] is:
[tex]\[ S = 1250 \, \text{m} \][/tex]
#### Part b: Perimeter formula
The formula to calculate the perimeter [tex]\( P \)[/tex] of a triangle is the sum of its three sides. For a triangle with sides [tex]\( a \)[/tex], [tex]\( b \)[/tex], and [tex]\( c \)[/tex]:
[tex]\[ P = a + b + c \][/tex]
In this problem, the perimeter is already given as [tex]\( 2500 \, \text{m} \)[/tex].
### Summary
- Value of [tex]\( S \)[/tex]:
[tex]\[ S = 1250 \, \text{m} \][/tex]
- Perimeter formula:
[tex]\[ P = a + b + c \][/tex]
These are the necessary values and formulas based on the given problem.
### Step-by-Step Solution:
#### Part a: Calculating the sides and [tex]\( S \)[/tex]
1. Understanding the ratio:
The sides of the triangle are in the ratio 6:9:10. Let's denote the sides as [tex]\( 6x \)[/tex], [tex]\( 9x \)[/tex], and [tex]\( 10x \)[/tex], where [tex]\( x \)[/tex] is a common multiplier.
2. Given perimeter:
The perimeter of the triangle is [tex]\( 2500 \, \text{m} \)[/tex].
Thus, we have:
[tex]\[ 6x + 9x + 10x = 2500 \][/tex]
3. Solving for [tex]\( x \)[/tex]:
Combine the terms on the left-hand side:
[tex]\[ 25x = 2500 \][/tex]
Divide both sides by 25:
[tex]\[ x = \frac{2500}{25} = 100 \][/tex]
4. Calculating the sides:
Using [tex]\( x = 100 \)[/tex]:
[tex]\[ a = 6x = 6 \times 100 = 600 \, \text{m} \][/tex]
[tex]\[ b = 9x = 9 \times 100 = 900 \, \text{m} \][/tex]
[tex]\[ c = 10x = 10 \times 100 = 1000 \, \text{m} \][/tex]
5. Calculating the semi-perimeter [tex]\( S \)[/tex]:
The semi-perimeter [tex]\( S \)[/tex] is half of the perimeter:
[tex]\[ S = \frac{\text{Perimeter}}{2} = \frac{2500}{2} = 1250 \, \text{m} \][/tex]
Therefore, the value of [tex]\( S \)[/tex] is:
[tex]\[ S = 1250 \, \text{m} \][/tex]
#### Part b: Perimeter formula
The formula to calculate the perimeter [tex]\( P \)[/tex] of a triangle is the sum of its three sides. For a triangle with sides [tex]\( a \)[/tex], [tex]\( b \)[/tex], and [tex]\( c \)[/tex]:
[tex]\[ P = a + b + c \][/tex]
In this problem, the perimeter is already given as [tex]\( 2500 \, \text{m} \)[/tex].
### Summary
- Value of [tex]\( S \)[/tex]:
[tex]\[ S = 1250 \, \text{m} \][/tex]
- Perimeter formula:
[tex]\[ P = a + b + c \][/tex]
These are the necessary values and formulas based on the given problem.
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.