Looking for answers? Westonci.ca is your go-to Q&A platform, offering quick, trustworthy responses from a community of experts. Discover a wealth of knowledge from experts across different disciplines on our comprehensive Q&A platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
To determine how many molecules are in a 23.45 g sample of copper (II) hydroxide, [tex]\( \text{Cu(OH)}_2 \)[/tex], we need to follow a series of steps involving dimensional analysis. Here’s how we break it down:
1. Determine the number of moles of [tex]\( \text{Cu(OH)}_2 \)[/tex] in the sample:
Given:
- Mass of the sample ([tex]\( m \)[/tex]): 23.45 g
- Molar mass of [tex]\( \text{Cu(OH)}_2 \)[/tex] ([tex]\( M \)[/tex]): 97.562 g/mol
The formula to find the number of moles ([tex]\( n \)[/tex]) is:
[tex]\[ n = \frac{m}{M} \][/tex]
Substituting the given values:
[tex]\[ n = \frac{23.45 \text{ g}}{97.562 \text{ g/mol}} \approx 0.24035997622024968 \text{ mol} \][/tex]
2. Calculate the number of molecules using Avogadro’s number:
Avogadro’s number ([tex]\( N_A \)[/tex]) tells us that one mole of any substance contains [tex]\( 6.022 \times 10^{23} \)[/tex] molecules.
The number of molecules ([tex]\( N \)[/tex]) can be calculated using the formula:
[tex]\[ N = n \times N_A \][/tex]
Substituting the previously calculated number of moles and Avogadro’s number:
[tex]\[ N = 0.24035997622024968 \text{ mol} \times 6.022 \times 10^{23} \text{ molecules/mol} \][/tex]
Performing the multiplication:
[tex]\[ N \approx 1.4474477767983435 \times 10^{23} \text{ molecules} \][/tex]
3. Expressing the answer with the correct number of significant figures:
The given mass of the sample (23.45 g) has 4 significant figures, and Avogadro's number is generally given to 4 significant figures for simplicity.
Therefore, the number of molecules should also be expressed with 4 significant figures:
[tex]\[ N \approx 1.447 \times 10^{23} \text{ molecules} \][/tex]
So, in a 23.45 g sample of copper (II) hydroxide ([tex]\( \text{Cu(OH)}_2 \)[/tex]), there are approximately [tex]\( 1.447 \times 10^{23} \)[/tex] molecules.
1. Determine the number of moles of [tex]\( \text{Cu(OH)}_2 \)[/tex] in the sample:
Given:
- Mass of the sample ([tex]\( m \)[/tex]): 23.45 g
- Molar mass of [tex]\( \text{Cu(OH)}_2 \)[/tex] ([tex]\( M \)[/tex]): 97.562 g/mol
The formula to find the number of moles ([tex]\( n \)[/tex]) is:
[tex]\[ n = \frac{m}{M} \][/tex]
Substituting the given values:
[tex]\[ n = \frac{23.45 \text{ g}}{97.562 \text{ g/mol}} \approx 0.24035997622024968 \text{ mol} \][/tex]
2. Calculate the number of molecules using Avogadro’s number:
Avogadro’s number ([tex]\( N_A \)[/tex]) tells us that one mole of any substance contains [tex]\( 6.022 \times 10^{23} \)[/tex] molecules.
The number of molecules ([tex]\( N \)[/tex]) can be calculated using the formula:
[tex]\[ N = n \times N_A \][/tex]
Substituting the previously calculated number of moles and Avogadro’s number:
[tex]\[ N = 0.24035997622024968 \text{ mol} \times 6.022 \times 10^{23} \text{ molecules/mol} \][/tex]
Performing the multiplication:
[tex]\[ N \approx 1.4474477767983435 \times 10^{23} \text{ molecules} \][/tex]
3. Expressing the answer with the correct number of significant figures:
The given mass of the sample (23.45 g) has 4 significant figures, and Avogadro's number is generally given to 4 significant figures for simplicity.
Therefore, the number of molecules should also be expressed with 4 significant figures:
[tex]\[ N \approx 1.447 \times 10^{23} \text{ molecules} \][/tex]
So, in a 23.45 g sample of copper (II) hydroxide ([tex]\( \text{Cu(OH)}_2 \)[/tex]), there are approximately [tex]\( 1.447 \times 10^{23} \)[/tex] molecules.
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.