Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Connect with a community of experts ready to provide precise solutions to your questions quickly and accurately. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
To find the equivalent value of [tex]\(\sin^{-1}\left(\cos\left(\frac{\pi}{2}\right)\right)\)[/tex], let's follow these steps carefully:
1. Evaluate the cosine function:
- We need to determine [tex]\(\cos\left(\frac{\pi}{2}\right)\)[/tex].
- The cosine of [tex]\(\frac{\pi}{2}\)[/tex] radians (or 90 degrees) is 0.
[tex]\[ \cos\left(\frac{\pi}{2}\right) = 0 \][/tex]
2. Apply the inverse sine function:
- Now we need to find [tex]\(\sin^{-1}(0)\)[/tex].
- The inverse sine function returns the angle whose sine is the given value. We need to find an angle [tex]\( \theta \)[/tex] such that [tex]\(\sin(\theta) = 0\)[/tex].
- Within the range of the inverse sine function [tex]\([- \frac{\pi}{2}, \frac{\pi}{2}]\)[/tex], the angle that satisfies [tex]\(\sin(\theta) = 0\)[/tex] is [tex]\( \theta = 0 \)[/tex].
3. Conclusion:
- Therefore, [tex]\(\sin^{-1}(0) = 0\)[/tex], and consequently:
[tex]\[ \sin^{-1}\left(\cos\left(\frac{\pi}{2}\right)\right) = \sin^{-1}(0) = 0 \][/tex]
Hence, the equivalent value of [tex]\(\sin^{-1}\left(\cos\left(\frac{\pi}{2}\right)\right)\)[/tex] in radians is [tex]\(0\)[/tex].
1. Evaluate the cosine function:
- We need to determine [tex]\(\cos\left(\frac{\pi}{2}\right)\)[/tex].
- The cosine of [tex]\(\frac{\pi}{2}\)[/tex] radians (or 90 degrees) is 0.
[tex]\[ \cos\left(\frac{\pi}{2}\right) = 0 \][/tex]
2. Apply the inverse sine function:
- Now we need to find [tex]\(\sin^{-1}(0)\)[/tex].
- The inverse sine function returns the angle whose sine is the given value. We need to find an angle [tex]\( \theta \)[/tex] such that [tex]\(\sin(\theta) = 0\)[/tex].
- Within the range of the inverse sine function [tex]\([- \frac{\pi}{2}, \frac{\pi}{2}]\)[/tex], the angle that satisfies [tex]\(\sin(\theta) = 0\)[/tex] is [tex]\( \theta = 0 \)[/tex].
3. Conclusion:
- Therefore, [tex]\(\sin^{-1}(0) = 0\)[/tex], and consequently:
[tex]\[ \sin^{-1}\left(\cos\left(\frac{\pi}{2}\right)\right) = \sin^{-1}(0) = 0 \][/tex]
Hence, the equivalent value of [tex]\(\sin^{-1}\left(\cos\left(\frac{\pi}{2}\right)\right)\)[/tex] in radians is [tex]\(0\)[/tex].
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.