Answered

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the graph of y= x^2-4x-1 is shown what is the range

Sagot :

Answer:

[-1,infinity)

Step-by-step explanation:

We want to find the minima or maxima of the quadratic (vertex)

Convert to vertex form:  y=x^2-4x-1

y=x^2-4x+4-5

y=(x-2)^2-1

Vertex is at (2,-1)

The graph opens up as the first term is positive

[-1,infinity) is the range

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