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Make [tex]\( x \)[/tex] the subject of the formula [tex]\( \quad a = \frac{x+c}{x-b} \)[/tex]

Sagot :

Certainly! Let's solve the equation [tex]\( a = \frac{x + c}{x - b} \)[/tex] to make [tex]\( x \)[/tex] the subject.

Step-by-Step Solution:

1. Start with the given equation:
[tex]\[ a = \frac{x + c}{x - b} \][/tex]

2. To clear the fraction, multiply both sides of the equation by [tex]\( x - b \)[/tex]:
[tex]\[ a(x - b) = x + c \][/tex]

3. Distribute [tex]\( a \)[/tex] on the left-hand side:
[tex]\[ ax - ab = x + c \][/tex]

4. To isolate [tex]\( x \)[/tex], first get all terms involving [tex]\( x \)[/tex] on one side of the equation and constant terms on the other side. Subtract [tex]\( x \)[/tex] from both sides:
[tex]\[ ax - x = ab + c \][/tex]

5. Factor [tex]\( x \)[/tex] out of the terms on the left side:
[tex]\[ x(a - 1) = ab + c \][/tex]

6. Solve for [tex]\( x \)[/tex] by dividing both sides of the equation by [tex]\( a - 1 \)[/tex]:
[tex]\[ x = \frac{ab + c}{a - 1} \][/tex]

So, the solution for [tex]\( x \)[/tex] in terms of [tex]\( a \)[/tex], [tex]\( b \)[/tex], and [tex]\( c \)[/tex] is:
[tex]\[ x = \frac{ab + c}{a - 1} \][/tex]