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Complete the table of values for the equation [tex]$y=5-x$[/tex].

\begin{tabular}{|c|c|c|c|}
\hline
[tex]$x$[/tex] & 0 & 1 & 2 \\
\hline
[tex]$y$[/tex] & & & \\
\hline
\end{tabular}

Sagot :

GinnyAnswer
Sure! To complete the table of values for the equation [tex]\( y = 5 - x \)[/tex], we need to substitute each [tex]\( x \)[/tex] value into the equation and find the corresponding [tex]\( y \)[/tex] value.

1. When [tex]\( x = 0 \)[/tex]:
[tex]\[ y = 5 - 0 = 5 \][/tex]

2. When [tex]\( x = 1 \)[/tex]:
[tex]\[ y = 5 - 1 = 4 \][/tex]

3. When [tex]\( x = 2 \)[/tex]:
[tex]\[ y = 5 - 2 = 3 \][/tex]

With these calculations, the completed table of values is:

[tex]\[ \begin{tabular}{|l|l|l|l|} \hline $x$ & 0 & 1 & 2 \\ \hline $y$ & 5 & 4 & 3 \\ \hline \end{tabular} \][/tex]
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