Welcome to Westonci.ca, where you can find answers to all your questions from a community of experienced professionals. Join our Q&A platform to get precise answers from experts in diverse fields and enhance your understanding. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
To find the center and the radius of the circle given by the equation [tex]\((x + 2)^2 + (y - 5)^2 = 49\)[/tex], we can follow these steps:
1. Identify the standard form of the circle's equation: The standard form of a circle's equation is [tex]\((x - h)^2 + (y - k)^2 = r^2\)[/tex], where [tex]\((h, k)\)[/tex] represents the center of the circle, and [tex]\(r\)[/tex] is the radius.
2. Compare the given equation to the standard form:
- The given equation is [tex]\((x + 2)^2 + (y - 5)^2 = 49\)[/tex].
- Here, [tex]\((x + 2)^2\)[/tex] can be rewritten as [tex]\((x - (-2))^2\)[/tex], thus identifying [tex]\(h = -2\)[/tex].
- Similarly, [tex]\((y - 5)^2\)[/tex] is already in the required form with [tex]\(k = 5\)[/tex].
3. Determine the values of [tex]\(h\)[/tex] and [tex]\(k\)[/tex]:
- From the comparison, we find that [tex]\(h = -2\)[/tex] and [tex]\(k = 5\)[/tex].
4. Find the radius: The right side of the equation represents [tex]\(r^2\)[/tex]:
- We have [tex]\(r^2 = 49\)[/tex].
- To find the radius [tex]\(r\)[/tex], take the square root of 49:
[tex]\[ r = \sqrt{49} = 7 \][/tex]
So, the circle's center has coordinates [tex]\((-2, 5)\)[/tex], and the radius is [tex]\(7\)[/tex] units long.
Therefore, the completed information is:
- Center coordinates: [tex]\((-2, 5)\)[/tex]
- Radius: [tex]\(7\)[/tex] units long
1. Identify the standard form of the circle's equation: The standard form of a circle's equation is [tex]\((x - h)^2 + (y - k)^2 = r^2\)[/tex], where [tex]\((h, k)\)[/tex] represents the center of the circle, and [tex]\(r\)[/tex] is the radius.
2. Compare the given equation to the standard form:
- The given equation is [tex]\((x + 2)^2 + (y - 5)^2 = 49\)[/tex].
- Here, [tex]\((x + 2)^2\)[/tex] can be rewritten as [tex]\((x - (-2))^2\)[/tex], thus identifying [tex]\(h = -2\)[/tex].
- Similarly, [tex]\((y - 5)^2\)[/tex] is already in the required form with [tex]\(k = 5\)[/tex].
3. Determine the values of [tex]\(h\)[/tex] and [tex]\(k\)[/tex]:
- From the comparison, we find that [tex]\(h = -2\)[/tex] and [tex]\(k = 5\)[/tex].
4. Find the radius: The right side of the equation represents [tex]\(r^2\)[/tex]:
- We have [tex]\(r^2 = 49\)[/tex].
- To find the radius [tex]\(r\)[/tex], take the square root of 49:
[tex]\[ r = \sqrt{49} = 7 \][/tex]
So, the circle's center has coordinates [tex]\((-2, 5)\)[/tex], and the radius is [tex]\(7\)[/tex] units long.
Therefore, the completed information is:
- Center coordinates: [tex]\((-2, 5)\)[/tex]
- Radius: [tex]\(7\)[/tex] units long
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.