Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Get detailed and precise answers to your questions from a dedicated community of experts on our Q&A platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
To determine the median number of siblings from the given survey data, let's follow these steps:
1. Create a List of All Data Points:
First, we need to list out each data point according to its frequency. Here’s the given table:
[tex]\[ \begin{array}{|c|c|} \hline \text{Number of siblings} & \text{Frequency} \\ \hline 0 & 9 \\ \hline 1 & 5 \\ \hline 2 & 7 \\ \hline 3 & 1 \\ \hline 4 & 3 \\ \hline \end{array} \][/tex]
Based on this table, we create a list with the number of siblings appearing according to their frequencies:
[tex]\[ [0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 3, 4, 4, 4] \][/tex]
2. Order the List:
The list is already ordered, but to ensure clarity, here it is again:
[tex]\[ [0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 3, 4, 4, 4] \][/tex]
3. Find the Median:
To find the median, we need to determine the middle value in this list. If the number of observations (n) is odd, the median is the middle number. If n is even, the median is the average of the two middle numbers.
- Count the total number of data points: [tex]\( n = 25 \)[/tex].
Since [tex]\( n = 25 \)[/tex], an odd number, the median is the middle value. The middle value is located at position:
[tex]\[ \frac{n + 1}{2} = \frac{25 + 1}{2} = 13 \][/tex]
So, the 13th value in the ordered list is the median. If we count the values:
[tex]\[ [0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, \mathbf{1}, 1, 2, 2, 2, 2, 2, 2, 2, 3, 4, 4, 4] \][/tex]
The 13th value is 1.
Therefore, the median number of siblings is 1.
1. Create a List of All Data Points:
First, we need to list out each data point according to its frequency. Here’s the given table:
[tex]\[ \begin{array}{|c|c|} \hline \text{Number of siblings} & \text{Frequency} \\ \hline 0 & 9 \\ \hline 1 & 5 \\ \hline 2 & 7 \\ \hline 3 & 1 \\ \hline 4 & 3 \\ \hline \end{array} \][/tex]
Based on this table, we create a list with the number of siblings appearing according to their frequencies:
[tex]\[ [0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 3, 4, 4, 4] \][/tex]
2. Order the List:
The list is already ordered, but to ensure clarity, here it is again:
[tex]\[ [0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 3, 4, 4, 4] \][/tex]
3. Find the Median:
To find the median, we need to determine the middle value in this list. If the number of observations (n) is odd, the median is the middle number. If n is even, the median is the average of the two middle numbers.
- Count the total number of data points: [tex]\( n = 25 \)[/tex].
Since [tex]\( n = 25 \)[/tex], an odd number, the median is the middle value. The middle value is located at position:
[tex]\[ \frac{n + 1}{2} = \frac{25 + 1}{2} = 13 \][/tex]
So, the 13th value in the ordered list is the median. If we count the values:
[tex]\[ [0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, \mathbf{1}, 1, 2, 2, 2, 2, 2, 2, 2, 3, 4, 4, 4] \][/tex]
The 13th value is 1.
Therefore, the median number of siblings is 1.
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.