Answered

Looking for answers? Westonci.ca is your go-to Q&A platform, offering quick, trustworthy responses from a community of experts. Discover in-depth solutions to your questions from a wide range of experts on our user-friendly Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

Here's the 2nd question. Calculate the distance between the electrostatic interaction of potassium and bromide ions which typically results in a molar Coulomb potential energy of (-)970 kJ/mol in nanometers. Charge of ions= 1.602x10^-19 C, permittity=8.854x10^-12C^2/Jm, 6.02x10^23/mol

Sagot :

MathPhys

Answer:

0.143 nm

Explanation:

The Coulomb potential energy between two charged particles can be found with:

[tex]\large \text{$ U=\ $} \LARGE \text{$ \frac{1}{4\pi \epsilon_0}\frac{q_1 q_2}{r} $}[/tex]

where

  • U is the electric potential energy
  • ε₀ is the vacuum permittivity (8.854×10⁻¹² C²/J/m)
  • q₁ and q₂ are the charges of the particles
  • r is the distance between the particles

Plug in values and solve for the distance r.

[tex]\large \text{$ U=\ $} \LARGE \text{$ \frac{1}{4\pi \epsilon_0}\frac{q_1 q_2}{r} $}\\\\\large \text{$ 970\frac{kJ}{mol}\times\frac{1\ mol}{6.02\times 10^{23}}\times\frac{1000 J}{kJ} =\ $} \LARGE \text{$ \frac{1}{4\pi \times (8.854\times10^{-12}\ C^2/J/m)}\frac{(1.602\times 10^{-19}\ C)^2}{r} $}\\\\\large \text{$ 1.611\times 10^{-18} J=\ $} \LARGE \text{$ \frac{2.307\times 10^{-28} Jm}{r} $}\\\\\large \text{$ r=1.43\times10^{-10}\ m $}\\\\\large \text{$ r=0.143\ nm $}[/tex]

Rounded to three significant figures, the distance between the ions is 0.143 nanometers.

Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.