Explore Westonci.ca, the leading Q&A site where experts provide accurate and helpful answers to all your questions. Get quick and reliable solutions to your questions from a community of experienced experts on our platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
Certainly! To find the principal amount [tex]\( P \)[/tex] using the continuous compound interest formula, we start with the formula:
[tex]\[ A = P \times e^{(r \times t)} \][/tex]
where:
- [tex]\( A \)[/tex] is the future value,
- [tex]\( P \)[/tex] is the principal amount (the initial amount of money),
- [tex]\( r \)[/tex] is the annual interest rate (as a decimal),
- [tex]\( t \)[/tex] is the time the money is invested for, in years, and
- [tex]\( e \)[/tex] is the base of the natural logarithm (approximately equal to 2.71828).
Given values:
- [tex]\( A = \$ 6,300 \)[/tex]
- [tex]\( r = 9.82\% = 0.0982 \)[/tex] (converted from percentage to decimal)
- [tex]\( t = 7 \)[/tex] years
We need to solve for [tex]\( P \)[/tex]. Start by rearranging the formula to solve for [tex]\( P \)[/tex]:
[tex]\[ P = \frac{A}{e^{(r \times t)}} \][/tex]
Now substitute the given values into the equation:
[tex]\[ P = \frac{6300}{e^{(0.0982 \times 7)}} \][/tex]
Thus:
[tex]\[ P = \frac{6300}{e^{0.6874}} \][/tex]
Evaluate the exponent first:
[tex]\[ e^{0.6874} \][/tex]
Using the constant [tex]\( e \)[/tex] (approximately 2.71828):
[tex]\[ e^{0.6874} \approx 1.98817 \][/tex]
Now substitute this back into the equation:
[tex]\[ P = \frac{6300}{1.98817} \][/tex]
Finally, perform the division:
[tex]\[ P \approx 3168.16 \][/tex]
Therefore, the principal amount [tex]\( P \)[/tex] is approximately:
[tex]\[ P = \$ 3168.16 \][/tex]
So, the principal amount rounded to two decimal places is [tex]\(\boxed{3168.16}\)[/tex].
[tex]\[ A = P \times e^{(r \times t)} \][/tex]
where:
- [tex]\( A \)[/tex] is the future value,
- [tex]\( P \)[/tex] is the principal amount (the initial amount of money),
- [tex]\( r \)[/tex] is the annual interest rate (as a decimal),
- [tex]\( t \)[/tex] is the time the money is invested for, in years, and
- [tex]\( e \)[/tex] is the base of the natural logarithm (approximately equal to 2.71828).
Given values:
- [tex]\( A = \$ 6,300 \)[/tex]
- [tex]\( r = 9.82\% = 0.0982 \)[/tex] (converted from percentage to decimal)
- [tex]\( t = 7 \)[/tex] years
We need to solve for [tex]\( P \)[/tex]. Start by rearranging the formula to solve for [tex]\( P \)[/tex]:
[tex]\[ P = \frac{A}{e^{(r \times t)}} \][/tex]
Now substitute the given values into the equation:
[tex]\[ P = \frac{6300}{e^{(0.0982 \times 7)}} \][/tex]
Thus:
[tex]\[ P = \frac{6300}{e^{0.6874}} \][/tex]
Evaluate the exponent first:
[tex]\[ e^{0.6874} \][/tex]
Using the constant [tex]\( e \)[/tex] (approximately 2.71828):
[tex]\[ e^{0.6874} \approx 1.98817 \][/tex]
Now substitute this back into the equation:
[tex]\[ P = \frac{6300}{1.98817} \][/tex]
Finally, perform the division:
[tex]\[ P \approx 3168.16 \][/tex]
Therefore, the principal amount [tex]\( P \)[/tex] is approximately:
[tex]\[ P = \$ 3168.16 \][/tex]
So, the principal amount rounded to two decimal places is [tex]\(\boxed{3168.16}\)[/tex].
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.