Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Get detailed and accurate answers to your questions from a community of experts on our comprehensive Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
To solve the problem, we need to find a number of eggs that satisfies the following conditions:
1. When the eggs are removed in groups of 3, there is 1 egg left.
2. When the eggs are removed in groups of 5, there is 1 egg left.
3. When the eggs are removed in groups of 7, there are no eggs left.
4. The total number of eggs is less than or equal to 100.
These conditions can be translated into a set of congruences:
[tex]\[ \text{(i)} \quad N \equiv 1 \pmod{3} \][/tex]
[tex]\[ \text{(ii)} \quad N \equiv 1 \pmod{5} \][/tex]
[tex]\[ \text{(iii)} \quad N \equiv 0 \pmod{7} \][/tex]
### Step-by-step Solution:
1. Let's consider the third condition first; this tells us that the number of eggs [tex]\( N \)[/tex] must be a multiple of 7. Therefore, we can write:
[tex]\[ N = 7k \text{ for some integer } k \][/tex]
2. Next, using the first condition, [tex]\( N \equiv 1 \pmod{3} \)[/tex], we substitute [tex]\( N \)[/tex] and get:
[tex]\[ 7k \equiv 1 \pmod{3} \][/tex]
This simplifies to:
[tex]\[ 7k \mod 3 = 1 \][/tex]
[tex]\[ k \equiv 1 \pmod{3} \][/tex]
[tex]\[ \Rightarrow k = 3m + 1 \text{ for some integer } m \][/tex]
Therefore, substituting back for [tex]\( N \)[/tex]:
[tex]\[ N = 7(3m + 1) \][/tex]
[tex]\[ N = 21m + 7 \][/tex]
3. Now we use the second condition, [tex]\( N \equiv 1 \pmod{5} \)[/tex], to find [tex]\( m \)[/tex]. Substitute [tex]\( N \)[/tex]:
[tex]\[ 21m + 7 \equiv 1 \pmod{5} \][/tex]
Simplifying, we have:
[tex]\[ 21m + 7 \equiv 1 \pmod{5} \][/tex]
[tex]\[ 21m \equiv -6 \pmod{5} \][/tex]
[tex]\[ 21m \equiv -1 \pmod{5} \][/tex]
[tex]\[ 21 \equiv 1 \pmod{5} \][/tex]
Hence:
[tex]\[ m \equiv -1 \pmod{5} \][/tex]
[tex]\[ m = 5n - 1 \text{ for some integer } n \][/tex]
4. Finally, substituting [tex]\( m \)[/tex] back into the equation for [tex]\( N \)[/tex]:
[tex]\[ N = 21(5n - 1) + 7 \][/tex]
[tex]\[ N = 105n - 21 + 7 \][/tex]
[tex]\[ N = 105n - 14 \][/tex]
Since the number of eggs must be less than or equal to 100:
[tex]\[ 105n - 14 \leq 100 \][/tex]
[tex]\[ 105n \leq 114 \][/tex]
[tex]\[ n \leq \frac{114}{105} \][/tex]
[tex]\[ n \leq 1.0857 \][/tex]
Since [tex]\( n \)[/tex] must be an integer, [tex]\( n = 1 \)[/tex]:
Hence,
[tex]\[ N = 105(1) - 14 \][/tex]
[tex]\[ N = 91 \][/tex]
Therefore, the woman has [tex]\(\boxed{91}\)[/tex] eggs.
1. When the eggs are removed in groups of 3, there is 1 egg left.
2. When the eggs are removed in groups of 5, there is 1 egg left.
3. When the eggs are removed in groups of 7, there are no eggs left.
4. The total number of eggs is less than or equal to 100.
These conditions can be translated into a set of congruences:
[tex]\[ \text{(i)} \quad N \equiv 1 \pmod{3} \][/tex]
[tex]\[ \text{(ii)} \quad N \equiv 1 \pmod{5} \][/tex]
[tex]\[ \text{(iii)} \quad N \equiv 0 \pmod{7} \][/tex]
### Step-by-step Solution:
1. Let's consider the third condition first; this tells us that the number of eggs [tex]\( N \)[/tex] must be a multiple of 7. Therefore, we can write:
[tex]\[ N = 7k \text{ for some integer } k \][/tex]
2. Next, using the first condition, [tex]\( N \equiv 1 \pmod{3} \)[/tex], we substitute [tex]\( N \)[/tex] and get:
[tex]\[ 7k \equiv 1 \pmod{3} \][/tex]
This simplifies to:
[tex]\[ 7k \mod 3 = 1 \][/tex]
[tex]\[ k \equiv 1 \pmod{3} \][/tex]
[tex]\[ \Rightarrow k = 3m + 1 \text{ for some integer } m \][/tex]
Therefore, substituting back for [tex]\( N \)[/tex]:
[tex]\[ N = 7(3m + 1) \][/tex]
[tex]\[ N = 21m + 7 \][/tex]
3. Now we use the second condition, [tex]\( N \equiv 1 \pmod{5} \)[/tex], to find [tex]\( m \)[/tex]. Substitute [tex]\( N \)[/tex]:
[tex]\[ 21m + 7 \equiv 1 \pmod{5} \][/tex]
Simplifying, we have:
[tex]\[ 21m + 7 \equiv 1 \pmod{5} \][/tex]
[tex]\[ 21m \equiv -6 \pmod{5} \][/tex]
[tex]\[ 21m \equiv -1 \pmod{5} \][/tex]
[tex]\[ 21 \equiv 1 \pmod{5} \][/tex]
Hence:
[tex]\[ m \equiv -1 \pmod{5} \][/tex]
[tex]\[ m = 5n - 1 \text{ for some integer } n \][/tex]
4. Finally, substituting [tex]\( m \)[/tex] back into the equation for [tex]\( N \)[/tex]:
[tex]\[ N = 21(5n - 1) + 7 \][/tex]
[tex]\[ N = 105n - 21 + 7 \][/tex]
[tex]\[ N = 105n - 14 \][/tex]
Since the number of eggs must be less than or equal to 100:
[tex]\[ 105n - 14 \leq 100 \][/tex]
[tex]\[ 105n \leq 114 \][/tex]
[tex]\[ n \leq \frac{114}{105} \][/tex]
[tex]\[ n \leq 1.0857 \][/tex]
Since [tex]\( n \)[/tex] must be an integer, [tex]\( n = 1 \)[/tex]:
Hence,
[tex]\[ N = 105(1) - 14 \][/tex]
[tex]\[ N = 91 \][/tex]
Therefore, the woman has [tex]\(\boxed{91}\)[/tex] eggs.
We appreciate your time. Please come back anytime for the latest information and answers to your questions. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.