Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Ask your questions and receive detailed answers from professionals with extensive experience in various fields. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

Select the correct answer.

If [tex]5(4-x)\ \textless \ y+12[/tex] and [tex]y+12\ \textless \ 3x+1[/tex], then which statement is true?

A. [tex]3x+1-5(4-x)=y+12[/tex]

B. [tex]5(4-x)+3x+1=y+12[/tex]

C. [tex]3x+1\ \textless \ 5(4+x)[/tex]

D. [tex]5(4-x)\ \textless \ 3x+1[/tex]


Sagot :

To determine which statement is true given the inequalities [tex]\(5(4-x) < y + 12\)[/tex] and [tex]\(y + 12 < 3x + 1\)[/tex], let's analyze each of the provided options step-by-step:

1. Option 1: [tex]\(3x + 1 - 5(4 - x) = y + 12\)[/tex]

Expanding and simplifying:
[tex]\[ 3x + 1 - 5(4 - x) = y + 12 \][/tex]
[tex]\[ 3x + 1 - 20 + 5x = y + 12 \][/tex]
[tex]\[ 8x - 19 = y + 12 \][/tex]
Substituting [tex]\(y + 12\)[/tex] does not yield both inequalities simultaneously, so we will consider other options.

2. Option 2: [tex]\(5(4 - x) + 3x + 1 = y + 12\)[/tex]

Expanding and simplifying:
[tex]\[ 5(4 - x) + 3x + 1 = y + 12 \][/tex]
[tex]\[ 20 - 5x + 3x + 1 = y + 12 \][/tex]
[tex]\[ 20 - 2x + 1 = y + 12 \][/tex]
[tex]\[ 21 - 2x = y + 12 \][/tex]
This equation does not fit the form of the given inequalities simultaneously, which leads us to check other options.

3. Option 3: [tex]\(3x + 1 < 5(4 + x)\)[/tex]

Expanding and simplifying:
[tex]\[ 3x + 1 < 5(4 + x) \][/tex]
[tex]\[ 3x + 1 < 20 + 5x \][/tex]
[tex]\[ 3x + 1 - 5x < 20 \][/tex]
[tex]\[ -2x + 1 < 20 \][/tex]
[tex]\[ -2x < 19 \][/tex]
[tex]\[ x > -\frac{19}{2} \][/tex]
This simplifies to [tex]\(x > -\frac{19}{2}\)[/tex]. However, this inequality being true does not guarantee that the given conditions hold simultaneously.

4. Option 4: [tex]\(5(4 - x) < 3x + 1\)[/tex]

Expanding and simplifying:
[tex]\[ 5(4 - x) < 3x + 1 \][/tex]
[tex]\[ 20 - 5x < 3x + 1 \][/tex]
[tex]\[ 20 - 1 < 3x + 5x \][/tex]
[tex]\[ 19 < 8x \][/tex]
[tex]\[ x > \frac{19}{8} \][/tex]
This indicates that [tex]\(x > \frac{19}{8}\)[/tex].

When [tex]\(x > \frac{19}{8}\)[/tex], it is consistent with the given inequalities [tex]\(5(4 - x) < y + 12\)[/tex] and [tex]\(y + 12 < 3x + 1\)[/tex]. Therefore, this inequality ensures that both conditions are satisfied.

Hence, the correct statement is:
[tex]\[ \boxed{5(4 - x) < 3x + 1} \][/tex]