Answered

Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Connect with a community of experts ready to help you find solutions to your questions quickly and accurately. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

Simplify [tex](32^4)^7 / 16^3[/tex], leaving answer as index notation

Simplify Tex3247 163tex Leaving Answer As Index Notation class=

Sagot :

Answer:

[tex]2^{128}[/tex]

Step-by-step explanation:

Using the properties of exponents

• [tex](a^m)^{n}[/tex] = [tex]a^{mn}[/tex]

• [tex]a^{m}[/tex] ÷ [tex]a^{n}[/tex] = [tex]a^{(m-n)}[/tex]

given

[tex](32^4)^{7}[/tex] ÷ 16³

express 32 as [tex]2^{5}[/tex] and 16 as [tex]2^{4}[/tex]

= ( [tex](2^5^{(4)})^7[/tex] ÷ ([tex]2^{4}[/tex] )³

= [tex](2^{20}) ^{7}[/tex] ÷ [tex]2^{12}[/tex]

= [tex]2^{140}[/tex] ÷ [tex]2^{12}[/tex]

= [tex]2^{(140-12)}[/tex]

= [tex]2^{128}[/tex]

We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.