Answered

Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Our platform connects you with professionals ready to provide precise answers to all your questions in various areas of expertise. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

Simplify [tex](32^4)^7 / 16^3[/tex], leaving answer as index notation

Simplify Tex3247 163tex Leaving Answer As Index Notation class=

Sagot :

Answer:

[tex]2^{128}[/tex]

Step-by-step explanation:

Using the properties of exponents

• [tex](a^m)^{n}[/tex] = [tex]a^{mn}[/tex]

• [tex]a^{m}[/tex] ÷ [tex]a^{n}[/tex] = [tex]a^{(m-n)}[/tex]

given

[tex](32^4)^{7}[/tex] ÷ 16³

express 32 as [tex]2^{5}[/tex] and 16 as [tex]2^{4}[/tex]

= ( [tex](2^5^{(4)})^7[/tex] ÷ ([tex]2^{4}[/tex] )³

= [tex](2^{20}) ^{7}[/tex] ÷ [tex]2^{12}[/tex]

= [tex]2^{140}[/tex] ÷ [tex]2^{12}[/tex]

= [tex]2^{(140-12)}[/tex]

= [tex]2^{128}[/tex]

Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.