Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

Simplify [tex](32^4)^7 / 16^3[/tex], leaving answer as index notation

Simplify Tex3247 163tex Leaving Answer As Index Notation class=

Sagot :

Answer:

[tex]2^{128}[/tex]

Step-by-step explanation:

Using the properties of exponents

• [tex](a^m)^{n}[/tex] = [tex]a^{mn}[/tex]

• [tex]a^{m}[/tex] ÷ [tex]a^{n}[/tex] = [tex]a^{(m-n)}[/tex]

given

[tex](32^4)^{7}[/tex] ÷ 16³

express 32 as [tex]2^{5}[/tex] and 16 as [tex]2^{4}[/tex]

= ( [tex](2^5^{(4)})^7[/tex] ÷ ([tex]2^{4}[/tex] )³

= [tex](2^{20}) ^{7}[/tex] ÷ [tex]2^{12}[/tex]

= [tex]2^{140}[/tex] ÷ [tex]2^{12}[/tex]

= [tex]2^{(140-12)}[/tex]

= [tex]2^{128}[/tex]

Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.