Discover a world of knowledge at Westonci.ca, where experts and enthusiasts come together to answer your questions. Connect with a community of experts ready to help you find solutions to your questions quickly and accurately. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

What is the electric force acting between two charges of [tex]-0.0050 \, C[/tex] and [tex]0.0050 \, C[/tex] that are [tex]0.025 \, m[/tex] apart?

Use [tex]F = \frac{k q_1 q_2}{r^2}[/tex] and [tex]k = 9.00 \times 10^9 \, N \cdot m^2 / C^2[/tex].

A. [tex]-3.6 \times 10^8 \, N[/tex]

B. [tex]3.6 \times 10^8 \, N[/tex]

C. [tex]-9.0 \times 10^6 \, N[/tex]

D. [tex]9.0 \times 10^6 \, N[/tex]

Sagot :

To find the electric force acting between two charges using Coulomb's law, we can follow these steps:

1. Identify the given values:
- Charge [tex]\( q_1 = -0.0050 \)[/tex] Coulombs (C)
- Charge [tex]\( q_2 = 0.0050 \)[/tex] Coulombs (C)
- Distance [tex]\( r = 0.025 \)[/tex] meters (m)
- Coulomb's constant [tex]\( k = 9.00 \times 10^9 \)[/tex] Newton meter squared per Coulomb squared (N·m²/C²)

2. Write down the formula for Coulomb's Law:
[tex]\[ F = \frac{k q_1 q_2}{r^2} \][/tex]

3. Substitute the given values into the formula:
[tex]\[ F = \frac{(9.00 \times 10^9) \times (-0.0050) \times (0.0050)}{(0.025)^2} \][/tex]

4. Calculate the denominator:
[tex]\[ (0.025)^2 = 0.000625 \][/tex]

5. Calculate the numerator:
[tex]\[ (9.00 \times 10^9) \times (-0.0050) \times (0.0050) = (9.00 \times 10^9) \times (-0.000025) = -225000000.0 \][/tex]

6. Divide the numerator by the denominator:
[tex]\[ F = \frac{-225000000.0}{0.000625} = -360000000.0 \text{ N} \][/tex]

7. Take the magnitude for the final choice selections:
The magnitude of the force is:
[tex]\[ |F| = 360000000.0 \text{ N} \][/tex]

Thus, the correct magnitude answer is:
[tex]\[ \boxed{3.6 \times 10^8 \text{ N}} \][/tex]

Let's match this with the given choices:
A. [tex]\(-3.6 \times 10^8 \text{ N}\)[/tex]
B. [tex]\(3.6 \times 10^8 \text{ N}\)[/tex]
C. [tex]\(-9.0 \times 10^6 \text{ N}\)[/tex]
D. [tex]\(9.0 \times 10^6 \text{ N}\)[/tex]

Therefore, the correct answer is:
[tex]\[ \boxed{B. \ 3.6 \times 10^8 \text{ N}} \][/tex]

This solution comprehends both the magnitude and the options given, but ensuring the final answer format adheres to positive magnitude considering the options provided.
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.