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Solve [tex]\( -6(4 - x) \leq -4(x + 1) \)[/tex]

A. [tex]\( x \geq 3 \)[/tex]

B. [tex]\( x \geq 2 \)[/tex]

C. [tex]\( x \leq 2 \)[/tex]

D. [tex]\( x \leq 3 \)[/tex]


Sagot :

To solve the inequality [tex]\( -6(4 - x) \leq -4(x + 1) \)[/tex], we will go through a step-by-step process of simplification and solving.

1. Distribute the constants inside the parentheses:
[tex]\[ -6(4 - x) \leq -4(x + 1) \][/tex]
Expanding both sides:
[tex]\[ -6 \cdot 4 + 6 \cdot x \leq -4 \cdot x - 4 \cdot 1 \][/tex]
Simplifying further:
[tex]\[ -24 + 6x \leq -4x - 4 \][/tex]

2. Combine the [tex]\(x\)[/tex] terms on one side and constants on the other side:
Add [tex]\(4x\)[/tex] to both sides to get all [tex]\(x\)[/tex] terms on the left:
[tex]\[ -24 + 6x + 4x \leq -4x + 4x - 4 \][/tex]
Simplifying this:
[tex]\[ -24 + 10x \leq -4 \][/tex]

3. Isolate the [tex]\(x\)[/tex] term by eliminating constants from the left side:
Add 24 to both sides:
[tex]\[ -24 + 24 + 10x \leq -4 + 24 \][/tex]
Simplifying this:
[tex]\[ 10x \leq 20 \][/tex]

4. Solve for [tex]\(x\)[/tex] by dividing both sides by 10:
[tex]\[ 10x \leq 20 \][/tex]
Dividing both sides by 10:
[tex]\[ x \leq \frac{20}{10} \][/tex]
Simplifying:
[tex]\[ x \leq 2 \][/tex]

Thus, the solution to the inequality [tex]\( -6(4 - x) \leq -4(x + 1) \)[/tex] is [tex]\( x \leq 2 \)[/tex].

Therefore, the correct answer is:
C. [tex]\( x \leq 2 \)[/tex]