At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Experience the ease of finding accurate answers to your questions from a knowledgeable community of professionals. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
Let's analyze the transformation [tex]\( g(x) = 5 f(x) \)[/tex] step-by-step to understand its effects on the original function [tex]\( f(x) \)[/tex].
### 1. Understanding the Transformation
The transformation [tex]\( g(x) = 5 f(x) \)[/tex] can be described as a vertical stretch of the original function [tex]\( f(x) \)[/tex] by a factor of 5. This means that for any given value of [tex]\( x \)[/tex], the output of [tex]\( f(x) \)[/tex] is multiplied by 5 to get [tex]\( g(x) \)[/tex].
### 2. Effects on the Slope
If the original function [tex]\( f(x) \)[/tex] is linear and can be expressed in the form [tex]\( f(x) = mx + b \)[/tex]:
- The slope of [tex]\( f(x) \)[/tex] is [tex]\( m \)[/tex].
- For the transformed function [tex]\( g(x) = 5 f(x) \)[/tex], this becomes [tex]\( g(x) = 5(mx + b) = 5mx + 5b \)[/tex].
So, the new slope becomes [tex]\( 5m \)[/tex], which means the slope is increased by a factor of 5. It does not change signs.
### 3. Effects on the Domain
The domain of the function [tex]\( f(x) \)[/tex] refers to all the input values [tex]\( x \)[/tex] for which the function is defined. Since the transformation [tex]\( g(x) = 5 f(x) \)[/tex] only involves scaling the output by 5 and does not change how [tex]\( x \)[/tex] is processed, the domain of the function remains unaffected. Therefore, the domain does not change.
### 4. Effects on the [tex]\( x \)[/tex]-Intercept
The [tex]\( x \)[/tex]-intercept is the point where the function crosses the [tex]\( x \)[/tex]-axis. For the original function [tex]\( f(x) \)[/tex]:
- The [tex]\( x \)[/tex]-intercept occurs where [tex]\( f(x) = 0 \)[/tex].
For the transformed function [tex]\( g(x) = 5 f(x) \)[/tex], the [tex]\( x \)[/tex]-intercept occurs where [tex]\( 5 f(x) = 0 \)[/tex]. Since multiplying zero by 5 still gives zero, the [tex]\( x \)[/tex]-intercept remains unchanged. Therefore, the [tex]\( x \)[/tex]-intercept does not increase by a multiple of 5.
### 5. Effects on the [tex]\( y \)[/tex]-Intercept
The [tex]\( y \)[/tex]-intercept is the point where the function crosses the [tex]\( y \)[/tex]-axis, i.e., where [tex]\( x = 0 \)[/tex].
For the original function [tex]\( f(x) \)[/tex]:
- The [tex]\( y \)[/tex]-intercept is [tex]\( f(0) = b \)[/tex], where [tex]\( b \)[/tex] is the constant term.
For the transformed function [tex]\( g(x) = 5 f(x) \)[/tex]:
- The [tex]\( y \)[/tex]-intercept is [tex]\( g(0) = 5 f(0) = 5b \)[/tex].
Therefore, if the [tex]\( y \)[/tex]-intercept of [tex]\( f(x) \)[/tex] is non-zero, it increases by a factor of 5.
### Conclusion
Based on our analysis, the correct effect of the transformation [tex]\( g(x) = 5 f(x) \)[/tex] on the original function [tex]\( f(x) \)[/tex] is:
- The [tex]\( y \)[/tex]-intercept increased by a multiple of 5.
Hence, the answer is:
The [tex]\( y \)[/tex]-intercept increased by a multiple of 5.
### 1. Understanding the Transformation
The transformation [tex]\( g(x) = 5 f(x) \)[/tex] can be described as a vertical stretch of the original function [tex]\( f(x) \)[/tex] by a factor of 5. This means that for any given value of [tex]\( x \)[/tex], the output of [tex]\( f(x) \)[/tex] is multiplied by 5 to get [tex]\( g(x) \)[/tex].
### 2. Effects on the Slope
If the original function [tex]\( f(x) \)[/tex] is linear and can be expressed in the form [tex]\( f(x) = mx + b \)[/tex]:
- The slope of [tex]\( f(x) \)[/tex] is [tex]\( m \)[/tex].
- For the transformed function [tex]\( g(x) = 5 f(x) \)[/tex], this becomes [tex]\( g(x) = 5(mx + b) = 5mx + 5b \)[/tex].
So, the new slope becomes [tex]\( 5m \)[/tex], which means the slope is increased by a factor of 5. It does not change signs.
### 3. Effects on the Domain
The domain of the function [tex]\( f(x) \)[/tex] refers to all the input values [tex]\( x \)[/tex] for which the function is defined. Since the transformation [tex]\( g(x) = 5 f(x) \)[/tex] only involves scaling the output by 5 and does not change how [tex]\( x \)[/tex] is processed, the domain of the function remains unaffected. Therefore, the domain does not change.
### 4. Effects on the [tex]\( x \)[/tex]-Intercept
The [tex]\( x \)[/tex]-intercept is the point where the function crosses the [tex]\( x \)[/tex]-axis. For the original function [tex]\( f(x) \)[/tex]:
- The [tex]\( x \)[/tex]-intercept occurs where [tex]\( f(x) = 0 \)[/tex].
For the transformed function [tex]\( g(x) = 5 f(x) \)[/tex], the [tex]\( x \)[/tex]-intercept occurs where [tex]\( 5 f(x) = 0 \)[/tex]. Since multiplying zero by 5 still gives zero, the [tex]\( x \)[/tex]-intercept remains unchanged. Therefore, the [tex]\( x \)[/tex]-intercept does not increase by a multiple of 5.
### 5. Effects on the [tex]\( y \)[/tex]-Intercept
The [tex]\( y \)[/tex]-intercept is the point where the function crosses the [tex]\( y \)[/tex]-axis, i.e., where [tex]\( x = 0 \)[/tex].
For the original function [tex]\( f(x) \)[/tex]:
- The [tex]\( y \)[/tex]-intercept is [tex]\( f(0) = b \)[/tex], where [tex]\( b \)[/tex] is the constant term.
For the transformed function [tex]\( g(x) = 5 f(x) \)[/tex]:
- The [tex]\( y \)[/tex]-intercept is [tex]\( g(0) = 5 f(0) = 5b \)[/tex].
Therefore, if the [tex]\( y \)[/tex]-intercept of [tex]\( f(x) \)[/tex] is non-zero, it increases by a factor of 5.
### Conclusion
Based on our analysis, the correct effect of the transformation [tex]\( g(x) = 5 f(x) \)[/tex] on the original function [tex]\( f(x) \)[/tex] is:
- The [tex]\( y \)[/tex]-intercept increased by a multiple of 5.
Hence, the answer is:
The [tex]\( y \)[/tex]-intercept increased by a multiple of 5.
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.