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1.3 If [tex]\sqrt[a]{2}=3[/tex], [tex]\sqrt[b]{3}=5[/tex], and [tex]\sqrt[c]{5}=8[/tex], determine the value of [tex]a \times b \times c[/tex].

Sagot :

Sure, let's go through the problem step-by-step to determine the value of [tex]\( a \times b \times c \)[/tex] given the equations:

1. [tex]\(\sqrt[a]{2} = 3\)[/tex]
2. [tex]\(\sqrt[b]{3} = 5\)[/tex]
3. [tex]\(\sqrt[c]{5} = 8\)[/tex]

### Step 1: Rewrite Each Root Expression

The expression [tex]\(\sqrt[a]{2} = 3\)[/tex] means that [tex]\( 2^{1/a} = 3 \)[/tex]. Taking the natural logarithm of both sides, we have:

[tex]\[ \log (2^{1/a}) = \log (3) \][/tex]

By using the logarithm properties, we get:

[tex]\[ \frac{\log (2)}{a} = \log (3) \][/tex]

Solving for [tex]\(a\)[/tex]:

[tex]\[ a = \frac{\log (2)}{\log (3)} \][/tex]

### Step 2: Solve for [tex]\(b\)[/tex]

Similarly, for [tex]\(\sqrt[b]{3} = 5\)[/tex]:

[tex]\[ 3^{1/b} = 5 \][/tex]

Taking the natural logarithm of both sides:

[tex]\[ \log (3^{1/b}) = \log (5) \][/tex]

Using the logarithm properties:

[tex]\[ \frac{\log (3)}{b} = \log (5) \][/tex]

Solving for [tex]\(b\)[/tex]:

[tex]\[ b = \frac{\log (3)}{\log (5)} \][/tex]

### Step 3: Solve for [tex]\(c\)[/tex]

For [tex]\(\sqrt[c]{5} = 8\)[/tex]:

[tex]\[ 5^{1/c} = 8 \][/tex]

Taking the natural logarithm of both sides:

[tex]\[ \log (5^{1/c}) = \log (8) \][/tex]

Using the logarithm properties:

[tex]\[ \frac{\log (5)}{c} = \log (8) \][/tex]

Solving for [tex]\(c\)[/tex]:

[tex]\[ c = \frac{\log (5)}{\log (8)} \][/tex]

### Step 4: Calculate [tex]\( a \times b \times c \)[/tex]

We now have expressions for [tex]\(a\)[/tex], [tex]\(b\)[/tex], and [tex]\(c\)[/tex]:

[tex]\[ a = \frac{\log (2)}{\log (3)} \][/tex]
[tex]\[ b = \frac{\log (3)}{\log (5)} \][/tex]
[tex]\[ c = \frac{\log (5)}{\log (8)} \][/tex]

Let's find the product [tex]\( a \times b \times c \)[/tex]:

[tex]\[ a \times b \times c = \left( \frac{\log (2)}{\log (3)} \right) \times \left( \frac{\log (3)}{\log (5)} \right) \times \left( \frac{\log (5)}{\log (8)} \right) \][/tex]

Notice that the logarithms cancel out sequentially:

[tex]\[ a \times b \times c = \frac{\log (2)}{\log (8)} \][/tex]

Since [tex]\(\log (8) = \log (2^3) = 3 \log (2)\)[/tex]:

[tex]\[ a \times b \times c = \frac{\log (2)}{3 \log (2)} = \frac{1}{3} \][/tex]

Therefore, the value of [tex]\( a \times b \times c \)[/tex] is:

[tex]\[ \boxed{\frac{1}{3}} \][/tex]
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