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What is the inverse of the function [tex]h(x) = \frac{3}{4} x + 12[/tex]?

[tex]h^{-1}(x) = \boxed{\phantom{}}[/tex]

Sagot :

To find the inverse of the function [tex]\( h(x) = \frac{3}{4} x + 12 \)[/tex], we follow these steps:

1. Rewrite the function using [tex]\( y \)[/tex] to denote the output:
[tex]\[ y = \frac{3}{4} x + 12 \][/tex]

2. Solve for [tex]\( x \)[/tex] in terms of [tex]\( y \)[/tex]:
- First, we isolate [tex]\( x \)[/tex]. Start by subtracting 12 from both sides of the equation:
[tex]\[ y - 12 = \frac{3}{4} x \][/tex]
- Next, to solve for [tex]\( x \)[/tex], we need to eliminate the fraction. Multiply both sides of the equation by the reciprocal of [tex]\( \frac{3}{4} \)[/tex], which is [tex]\( \frac{4}{3} \)[/tex]:
[tex]\[ x = \frac{4}{3} (y - 12) \][/tex]

3. Express the inverse function [tex]\( h^{-1}(x) \)[/tex]:
- We replace [tex]\( y \)[/tex] with [tex]\( x \)[/tex] to represent the input variable of the inverse function:
[tex]\[ h^{-1}(x) = \frac{4}{3} (x - 12) \][/tex]

Thus, the inverse of the function [tex]\( h(x) \)[/tex] is:
[tex]\[ h^{-1}(x) = \frac{4}{3} (x - 12) \][/tex]