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Question 2 (Multiple Choice Worth 5 points)

(Rearranging Equations and Formulas [tex]$LC$[/tex])

The equation for the area of a regular polygon is
[tex]\[ A = \frac{1}{2} P a \][/tex]

Solve the equation for [tex]$a$[/tex].

A. [tex]\( a = \frac{2A}{P} \)[/tex]

B. [tex]\( a = 2PA \)[/tex]

C. [tex]\( a = A - 2P \)[/tex]

D. [tex]\( a = \frac{P}{2A} \)[/tex]

Sagot :

GinnyAnswer
Sure! Let's solve the given equation [tex]\( A = \frac{1}{2} P a \)[/tex] for [tex]\( a \)[/tex].

The process involves isolating the variable [tex]\( a \)[/tex] on one side of the equation. Here are the steps:

1. Start with the given equation:
[tex]\[ A = \frac{1}{2} P a \][/tex]

2. To isolate [tex]\( a \)[/tex], first eliminate the fraction by multiplying both sides of the equation by 2:
[tex]\[ 2A = P a \][/tex]

3. Next, solve for [tex]\( a \)[/tex] by dividing both sides of the equation by [tex]\( P \)[/tex]:
[tex]\[ a = \frac{2A}{P} \][/tex]

So, the solution for [tex]\( a \)[/tex] is:
[tex]\[ a = \frac{2A}{P} \][/tex]

Therefore, the correct answer is:
[tex]\[ a = \frac{2 A}{\rho} \][/tex]
tristan5394

Answer:

A. [tex]\frac{2A}{P}=a[/tex]

Step-by-step explanation:

Start with [tex]A=\frac{1}2Pa[/tex]

2A = Pa (Multiply both sides by 2)

[tex]\frac{2A}{P}=a[/tex] (Divide both sides by P)

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