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Sagot :
To find the kinetic energy of the toy truck, we will use the formula for kinetic energy:
[tex]\[ KE = \frac{1}{2} m v^2 \][/tex]
Here, the variables are:
- [tex]\( m = 0.75 \)[/tex] kg (mass of the toy truck),
- [tex]\( v = 4 \)[/tex] m/s (velocity of the toy truck).
Let's plug these values into the formula:
[tex]\[ KE = \frac{1}{2} \times 0.75 \times (4)^2 \][/tex]
First, we calculate the square of the velocity:
[tex]\[ (4)^2 = 16 \][/tex]
Next, we multiply this result by the mass:
[tex]\[ 0.75 \times 16 = 12 \][/tex]
Finally, we take half of this product:
[tex]\[ KE = \frac{1}{2} \times 12 = 6 \][/tex]
Therefore, the kinetic energy of the toy truck is:
[tex]\[ 6 \, \text{J} \][/tex]
So, the correct answer is:
[tex]\[ \boxed{6 \, \text{J}} \][/tex]
[tex]\[ KE = \frac{1}{2} m v^2 \][/tex]
Here, the variables are:
- [tex]\( m = 0.75 \)[/tex] kg (mass of the toy truck),
- [tex]\( v = 4 \)[/tex] m/s (velocity of the toy truck).
Let's plug these values into the formula:
[tex]\[ KE = \frac{1}{2} \times 0.75 \times (4)^2 \][/tex]
First, we calculate the square of the velocity:
[tex]\[ (4)^2 = 16 \][/tex]
Next, we multiply this result by the mass:
[tex]\[ 0.75 \times 16 = 12 \][/tex]
Finally, we take half of this product:
[tex]\[ KE = \frac{1}{2} \times 12 = 6 \][/tex]
Therefore, the kinetic energy of the toy truck is:
[tex]\[ 6 \, \text{J} \][/tex]
So, the correct answer is:
[tex]\[ \boxed{6 \, \text{J}} \][/tex]
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