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What is the vertex of the parabola given by [tex]y = -(x-2)^2 - 1[/tex]?

A. [tex](2, 1)[/tex]
B. [tex](2, -1)[/tex]
C. [tex](-2, 1)[/tex]
D. [tex](-1, 2)[/tex]

Sagot :

GinnyAnswer
To determine the vertex of the parabola given by the equation [tex]\( y = -(x - 2)^2 - 1 \)[/tex], we can use the form of a parabola in vertex form, which is:

[tex]\[ y = a(x - h)^2 + k \][/tex]

In this form, [tex]\((h, k)\)[/tex] represents the vertex of the parabola. Comparing the given equation to the standard vertex form, we can identify:
- [tex]\( a = -1 \)[/tex]
- [tex]\( h = 2 \)[/tex]
- [tex]\( k = -1 \)[/tex]

Thus, the vertex of the parabola is [tex]\((h, k) = (2, -1)\)[/tex].

Therefore, the correct answer is:
B. [tex]\((2, -1)\)[/tex]
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