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Sagot :
Let's analyze the chemical reaction given:
[tex]\[ \text{NH}_4\text{OH} \rightarrow \text{NH}_3 + \text{H}_2\text{O} \][/tex]
Here, [tex]\(\text{NH}_4\text{OH}\)[/tex] (ammonium hydroxide) breaks down to form [tex]\(\text{NH}_3\)[/tex] (ammonia) and [tex]\(\text{H}_2\text{O}\)[/tex] (water).
In any chemical equation:
- The substances written on the left side of the arrow are called reactants.
- The substances written on the right side of the arrow are called products.
For this specific reaction:
- [tex]\(\text{NH}_4\text{OH}\)[/tex] is on the left side of the arrow, so it is a reactant.
- [tex]\(\text{NH}_3\)[/tex] and [tex]\(\text{H}_2\text{O}\)[/tex] are on the right side of the arrow, so they are products.
Thus:
- Ammonia ([tex]\(\text{NH}_3\)[/tex]) is a product.
- Ammonium hydroxide ([tex]\(\text{NH}_4\text{OH}\)[/tex]) is a reactant.
Therefore, in this reaction:
- Ammonia ([tex]\(\text{NH}_3\)[/tex]) is a product.
- Ammonium hydroxide ([tex]\(\text{NH}_4\text{OH}\)[/tex]) is a reactant.
[tex]\[ \text{NH}_4\text{OH} \rightarrow \text{NH}_3 + \text{H}_2\text{O} \][/tex]
Here, [tex]\(\text{NH}_4\text{OH}\)[/tex] (ammonium hydroxide) breaks down to form [tex]\(\text{NH}_3\)[/tex] (ammonia) and [tex]\(\text{H}_2\text{O}\)[/tex] (water).
In any chemical equation:
- The substances written on the left side of the arrow are called reactants.
- The substances written on the right side of the arrow are called products.
For this specific reaction:
- [tex]\(\text{NH}_4\text{OH}\)[/tex] is on the left side of the arrow, so it is a reactant.
- [tex]\(\text{NH}_3\)[/tex] and [tex]\(\text{H}_2\text{O}\)[/tex] are on the right side of the arrow, so they are products.
Thus:
- Ammonia ([tex]\(\text{NH}_3\)[/tex]) is a product.
- Ammonium hydroxide ([tex]\(\text{NH}_4\text{OH}\)[/tex]) is a reactant.
Therefore, in this reaction:
- Ammonia ([tex]\(\text{NH}_3\)[/tex]) is a product.
- Ammonium hydroxide ([tex]\(\text{NH}_4\text{OH}\)[/tex]) is a reactant.
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