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If [tex]P(x, y)[/tex] is the point on the unit circle defined by real number [tex]\theta[/tex], then [tex]\csc \theta =[/tex]

A. [tex]\frac{1}{x}[/tex]

B. [tex]\frac{y}{x}[/tex]

C. [tex]\frac{1}{y}[/tex]

D. [tex]\frac{x}{y}[/tex]

Sagot :

To solve the problem, we need to understand the relationship between the cosecant function and the unit circle. Let's break it down step-by-step:

1. Unit Circle Definition: On the unit circle, a point [tex]\(P(x, y)\)[/tex] is defined for an angle [tex]\(\theta\)[/tex], where:
- [tex]\(x = \cos \theta\)[/tex]
- [tex]\(y = \sin \theta\)[/tex]

2. Cosecant Function: The cosecant function, [tex]\(\csc \theta\)[/tex], is the reciprocal of the sine function:
- [tex]\(\csc \theta = \frac{1}{\sin \theta}\)[/tex]

3. Substitute Sin [tex]\(\theta\)[/tex]:
- Since [tex]\(y = \sin \theta\)[/tex], we can substitute [tex]\(y\)[/tex] into the cosecant function formula.
- Therefore, [tex]\(\csc \theta = \frac{1}{\sin \theta} = \frac{1}{y}\)[/tex]

Thus, the value of [tex]\(\csc \theta\)[/tex] is [tex]\(\frac{1}{y}\)[/tex].

Consequently, the correct choice is:
[tex]\[ \boxed{3} \][/tex]