Discover the answers you need at Westonci.ca, where experts provide clear and concise information on various topics. Join our platform to connect with experts ready to provide precise answers to your questions in different areas. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
Let's analyze each table to determine which one represents an exponential function.
### Table 1:
[tex]\[ \begin{tabular}{|c|c|} \hline $x$ & $f(x)$ \\ \hline 0 & 1 \\ \hline 1 & 3 \\ \hline 2 & 5 \\ \hline 3 & 8 \\ \hline 4 & 11 \\ \hline \end{tabular} \][/tex]
An exponential function has the form [tex]\( f(x) = a \cdot b^x \)[/tex] where [tex]\( a \)[/tex] and [tex]\( b \)[/tex] are constants. Let's examine the ratios of successive [tex]\( f(x) \)[/tex] values:
[tex]\[ \frac{f(1)}{f(0)} = \frac{3}{1} = 3 \][/tex]
[tex]\[ \frac{f(2)}{f(1)} = \frac{5}{3} \approx 1.67 \][/tex]
[tex]\[ \frac{f(3)}{f(2)} = \frac{8}{5} = 1.6 \][/tex]
[tex]\[ \frac{f(4)}{f(3)} = \frac{11}{8} \approx 1.375 \][/tex]
The ratios are not constant, suggesting that this table does not represent an exponential function.
### Table 2:
[tex]\[ \begin{tabular}{|c|c|} \hline $x$ & $f(x)$ \\ \hline 0 & 1 \\ \hline 1 & 4 \\ \hline 2 & 16 \\ \hline 3 & 64 \\ \hline 4 & 256 \\ \hline \end{tabular} \][/tex]
Again, we examine the ratios of successive [tex]\( f(x) \)[/tex] values:
[tex]\[ \frac{f(1)}{f(0)} = \frac{4}{1} = 4 \][/tex]
[tex]\[ \frac{f(2)}{f(1)} = \frac{16}{4} = 4 \][/tex]
[tex]\[ \frac{f(3)}{f(2)} = \frac{64}{16} = 4 \][/tex]
[tex]\[ \frac{f(4)}{f(3)} = \frac{256}{64} = 4 \][/tex]
The ratios are constant and equal to 4, suggesting that the function [tex]\( f(x) \)[/tex] in this table can be described by an exponential equation of the form [tex]\( f(x) = 1 \cdot 4^x \)[/tex]. Thus, Table 2 represents an exponential function.
### Table 3:
[tex]\[ \begin{tabular}{|c|c|} \hline $x$ & $f(x)$ \\ \hline 0 & 2 \\ \hline 1 & 4 \\ \hline 2 & 6 \\ \hline 3 & 10 \\ \hline 4 & 12 \\ \hline \end{tabular} \][/tex]
Again, we examine the ratios of successive [tex]\( f(x) \)[/tex] values:
[tex]\[ \frac{f(1)}{f(0)} = \frac{4}{2} = 2 \][/tex]
[tex]\[ \frac{f(2)}{f(1)} = \frac{6}{4} = 1.5 \][/tex]
[tex]\[ \frac{f(3)}{f(2)} = \frac{10}{6} \approx 1.67 \][/tex]
[tex]\[ \frac{f(4)}{f(3)} = \frac{12}{10} = 1.2 \][/tex]
The ratios are not constant, suggesting that this table does not represent an exponential function.
### Conclusion
Of the provided tables, only Table 2 consistently shows constant ratios between successive [tex]\( f(x) \)[/tex] values, which is characteristic of an exponential function. Therefore, Table 2 represents an exponential function.
### Table 1:
[tex]\[ \begin{tabular}{|c|c|} \hline $x$ & $f(x)$ \\ \hline 0 & 1 \\ \hline 1 & 3 \\ \hline 2 & 5 \\ \hline 3 & 8 \\ \hline 4 & 11 \\ \hline \end{tabular} \][/tex]
An exponential function has the form [tex]\( f(x) = a \cdot b^x \)[/tex] where [tex]\( a \)[/tex] and [tex]\( b \)[/tex] are constants. Let's examine the ratios of successive [tex]\( f(x) \)[/tex] values:
[tex]\[ \frac{f(1)}{f(0)} = \frac{3}{1} = 3 \][/tex]
[tex]\[ \frac{f(2)}{f(1)} = \frac{5}{3} \approx 1.67 \][/tex]
[tex]\[ \frac{f(3)}{f(2)} = \frac{8}{5} = 1.6 \][/tex]
[tex]\[ \frac{f(4)}{f(3)} = \frac{11}{8} \approx 1.375 \][/tex]
The ratios are not constant, suggesting that this table does not represent an exponential function.
### Table 2:
[tex]\[ \begin{tabular}{|c|c|} \hline $x$ & $f(x)$ \\ \hline 0 & 1 \\ \hline 1 & 4 \\ \hline 2 & 16 \\ \hline 3 & 64 \\ \hline 4 & 256 \\ \hline \end{tabular} \][/tex]
Again, we examine the ratios of successive [tex]\( f(x) \)[/tex] values:
[tex]\[ \frac{f(1)}{f(0)} = \frac{4}{1} = 4 \][/tex]
[tex]\[ \frac{f(2)}{f(1)} = \frac{16}{4} = 4 \][/tex]
[tex]\[ \frac{f(3)}{f(2)} = \frac{64}{16} = 4 \][/tex]
[tex]\[ \frac{f(4)}{f(3)} = \frac{256}{64} = 4 \][/tex]
The ratios are constant and equal to 4, suggesting that the function [tex]\( f(x) \)[/tex] in this table can be described by an exponential equation of the form [tex]\( f(x) = 1 \cdot 4^x \)[/tex]. Thus, Table 2 represents an exponential function.
### Table 3:
[tex]\[ \begin{tabular}{|c|c|} \hline $x$ & $f(x)$ \\ \hline 0 & 2 \\ \hline 1 & 4 \\ \hline 2 & 6 \\ \hline 3 & 10 \\ \hline 4 & 12 \\ \hline \end{tabular} \][/tex]
Again, we examine the ratios of successive [tex]\( f(x) \)[/tex] values:
[tex]\[ \frac{f(1)}{f(0)} = \frac{4}{2} = 2 \][/tex]
[tex]\[ \frac{f(2)}{f(1)} = \frac{6}{4} = 1.5 \][/tex]
[tex]\[ \frac{f(3)}{f(2)} = \frac{10}{6} \approx 1.67 \][/tex]
[tex]\[ \frac{f(4)}{f(3)} = \frac{12}{10} = 1.2 \][/tex]
The ratios are not constant, suggesting that this table does not represent an exponential function.
### Conclusion
Of the provided tables, only Table 2 consistently shows constant ratios between successive [tex]\( f(x) \)[/tex] values, which is characteristic of an exponential function. Therefore, Table 2 represents an exponential function.
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.