At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Join our platform to connect with experts ready to provide precise answers to your questions in different areas. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
Let's analyze each table to determine which one represents an exponential function.
### Table 1:
[tex]\[ \begin{tabular}{|c|c|} \hline $x$ & $f(x)$ \\ \hline 0 & 1 \\ \hline 1 & 3 \\ \hline 2 & 5 \\ \hline 3 & 8 \\ \hline 4 & 11 \\ \hline \end{tabular} \][/tex]
An exponential function has the form [tex]\( f(x) = a \cdot b^x \)[/tex] where [tex]\( a \)[/tex] and [tex]\( b \)[/tex] are constants. Let's examine the ratios of successive [tex]\( f(x) \)[/tex] values:
[tex]\[ \frac{f(1)}{f(0)} = \frac{3}{1} = 3 \][/tex]
[tex]\[ \frac{f(2)}{f(1)} = \frac{5}{3} \approx 1.67 \][/tex]
[tex]\[ \frac{f(3)}{f(2)} = \frac{8}{5} = 1.6 \][/tex]
[tex]\[ \frac{f(4)}{f(3)} = \frac{11}{8} \approx 1.375 \][/tex]
The ratios are not constant, suggesting that this table does not represent an exponential function.
### Table 2:
[tex]\[ \begin{tabular}{|c|c|} \hline $x$ & $f(x)$ \\ \hline 0 & 1 \\ \hline 1 & 4 \\ \hline 2 & 16 \\ \hline 3 & 64 \\ \hline 4 & 256 \\ \hline \end{tabular} \][/tex]
Again, we examine the ratios of successive [tex]\( f(x) \)[/tex] values:
[tex]\[ \frac{f(1)}{f(0)} = \frac{4}{1} = 4 \][/tex]
[tex]\[ \frac{f(2)}{f(1)} = \frac{16}{4} = 4 \][/tex]
[tex]\[ \frac{f(3)}{f(2)} = \frac{64}{16} = 4 \][/tex]
[tex]\[ \frac{f(4)}{f(3)} = \frac{256}{64} = 4 \][/tex]
The ratios are constant and equal to 4, suggesting that the function [tex]\( f(x) \)[/tex] in this table can be described by an exponential equation of the form [tex]\( f(x) = 1 \cdot 4^x \)[/tex]. Thus, Table 2 represents an exponential function.
### Table 3:
[tex]\[ \begin{tabular}{|c|c|} \hline $x$ & $f(x)$ \\ \hline 0 & 2 \\ \hline 1 & 4 \\ \hline 2 & 6 \\ \hline 3 & 10 \\ \hline 4 & 12 \\ \hline \end{tabular} \][/tex]
Again, we examine the ratios of successive [tex]\( f(x) \)[/tex] values:
[tex]\[ \frac{f(1)}{f(0)} = \frac{4}{2} = 2 \][/tex]
[tex]\[ \frac{f(2)}{f(1)} = \frac{6}{4} = 1.5 \][/tex]
[tex]\[ \frac{f(3)}{f(2)} = \frac{10}{6} \approx 1.67 \][/tex]
[tex]\[ \frac{f(4)}{f(3)} = \frac{12}{10} = 1.2 \][/tex]
The ratios are not constant, suggesting that this table does not represent an exponential function.
### Conclusion
Of the provided tables, only Table 2 consistently shows constant ratios between successive [tex]\( f(x) \)[/tex] values, which is characteristic of an exponential function. Therefore, Table 2 represents an exponential function.
### Table 1:
[tex]\[ \begin{tabular}{|c|c|} \hline $x$ & $f(x)$ \\ \hline 0 & 1 \\ \hline 1 & 3 \\ \hline 2 & 5 \\ \hline 3 & 8 \\ \hline 4 & 11 \\ \hline \end{tabular} \][/tex]
An exponential function has the form [tex]\( f(x) = a \cdot b^x \)[/tex] where [tex]\( a \)[/tex] and [tex]\( b \)[/tex] are constants. Let's examine the ratios of successive [tex]\( f(x) \)[/tex] values:
[tex]\[ \frac{f(1)}{f(0)} = \frac{3}{1} = 3 \][/tex]
[tex]\[ \frac{f(2)}{f(1)} = \frac{5}{3} \approx 1.67 \][/tex]
[tex]\[ \frac{f(3)}{f(2)} = \frac{8}{5} = 1.6 \][/tex]
[tex]\[ \frac{f(4)}{f(3)} = \frac{11}{8} \approx 1.375 \][/tex]
The ratios are not constant, suggesting that this table does not represent an exponential function.
### Table 2:
[tex]\[ \begin{tabular}{|c|c|} \hline $x$ & $f(x)$ \\ \hline 0 & 1 \\ \hline 1 & 4 \\ \hline 2 & 16 \\ \hline 3 & 64 \\ \hline 4 & 256 \\ \hline \end{tabular} \][/tex]
Again, we examine the ratios of successive [tex]\( f(x) \)[/tex] values:
[tex]\[ \frac{f(1)}{f(0)} = \frac{4}{1} = 4 \][/tex]
[tex]\[ \frac{f(2)}{f(1)} = \frac{16}{4} = 4 \][/tex]
[tex]\[ \frac{f(3)}{f(2)} = \frac{64}{16} = 4 \][/tex]
[tex]\[ \frac{f(4)}{f(3)} = \frac{256}{64} = 4 \][/tex]
The ratios are constant and equal to 4, suggesting that the function [tex]\( f(x) \)[/tex] in this table can be described by an exponential equation of the form [tex]\( f(x) = 1 \cdot 4^x \)[/tex]. Thus, Table 2 represents an exponential function.
### Table 3:
[tex]\[ \begin{tabular}{|c|c|} \hline $x$ & $f(x)$ \\ \hline 0 & 2 \\ \hline 1 & 4 \\ \hline 2 & 6 \\ \hline 3 & 10 \\ \hline 4 & 12 \\ \hline \end{tabular} \][/tex]
Again, we examine the ratios of successive [tex]\( f(x) \)[/tex] values:
[tex]\[ \frac{f(1)}{f(0)} = \frac{4}{2} = 2 \][/tex]
[tex]\[ \frac{f(2)}{f(1)} = \frac{6}{4} = 1.5 \][/tex]
[tex]\[ \frac{f(3)}{f(2)} = \frac{10}{6} \approx 1.67 \][/tex]
[tex]\[ \frac{f(4)}{f(3)} = \frac{12}{10} = 1.2 \][/tex]
The ratios are not constant, suggesting that this table does not represent an exponential function.
### Conclusion
Of the provided tables, only Table 2 consistently shows constant ratios between successive [tex]\( f(x) \)[/tex] values, which is characteristic of an exponential function. Therefore, Table 2 represents an exponential function.
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.