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## Sagot :

From the table:

- The number of households with 1 pet and no children is 53.

- The number of households with 2 pets and children is 85.

Given these numbers, the total number of households in the survey is 335.

Now, let's look at the likelihoods:

1.

**Number of households with 1 pet and no children: 53**

- Total households = 335

- Probability = Number of households with 1 pet and no children / Total households

- Probability = 53 / 335

- Probability ≈ 0.1582 (or 15.82%)

2.

**Number of households with 2 pets and children: 85**

- Total households = 335

- Probability = Number of households with 2 pets and children / Total households

- Probability = 85 / 335

- Probability ≈ 0.2537 (or 25.37%)

Comparing the two probabilities:

- The probability of a household having 1 pet and no children is approximately 15.82%.

- The probability of a household having 2 pets and children is approximately 25.37%.

Since the probability of having 2 pets and children (25.37%) is higher than the probability of having 1 pet and no children (15.82%), we can conclude that a customer is more likely to have 2 pets and children than to have 1 pet and no children.

Therefore, the completed statement should be:

A customer is more likely to have 1 pet and no children than they are to have

**a different scenario**.