Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Discover precise answers to your questions from a wide range of experts on our user-friendly Q&A platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
To simplify the expression [tex]\(\sqrt[3]{125 x^2 y^7}\)[/tex] using rational exponent properties and the definition of a radical in terms of exponents, we can break it down step-by-step as follows:
[tex]\[ \begin{array}{|l|l|} \hline \text{Step 1} & \sqrt[3]{125 x^2 y^7} \\ \hline \text{Step 2} & 125^{1/3} (x^2)^{1/3} (y^7)^{1/3} \\ \hline \text{Step 3} & 5 \cdot x^{2/3} \cdot y^{7/3} \\ \hline \text{Step 4} & 5 \cdot x^{2/3} \cdot y^{2 + 1/3} \\ \hline \text{Step 5} & 5 \cdot x^{2/3} \cdot y^2 \cdot y^{1/3} \\ \hline \text{Step 6} & 5y^2 \cdot x^{2/3} \cdot y^{1/3} \\ \hline \text{Step 7} & 5y^2 \cdot xy^{1/3} \\ \hline \end{array} \][/tex]
Explanation of each step:
- Step 1: Start with the given expression [tex]\(\sqrt[3]{125 x^2 y^7}\)[/tex].
- Step 2: Express the cube root in terms of rational exponents: [tex]\(125^{1/3} (x^2)^{1/3} (y^7)^{1/3}\)[/tex].
- Step 3: Simplify each term separately. [tex]\(125^{1/3} = 5\)[/tex], [tex]\((x^2)^{1/3} = x^{2/3}\)[/tex], [tex]\((y^7)^{1/3} = y^{7/3}\)[/tex].
- Step 4: Decompose [tex]\(y^{7/3}\)[/tex] into [tex]\(y^2 \cdot y^{1/3}\)[/tex] by writing [tex]\(7/3\)[/tex] as [tex]\(2 + 1/3\)[/tex].
- Step 5: Combine the terms to separate out [tex]\(y^2\)[/tex] and [tex]\(y^{1/3}\)[/tex].
- Step 6: Rewrite the combined term for clarity: [tex]\(5y^2 \cdot x^{2/3} \cdot y^{1/3}\)[/tex].
- Step 7: Re-arrange the terms, if needed, for standard form: [tex]\(5y^2 \cdot x^{2/3} \cdot y^{1/3}\)[/tex].
[tex]\[ \begin{array}{|l|l|} \hline \text{Step 1} & \sqrt[3]{125 x^2 y^7} \\ \hline \text{Step 2} & 125^{1/3} (x^2)^{1/3} (y^7)^{1/3} \\ \hline \text{Step 3} & 5 \cdot x^{2/3} \cdot y^{7/3} \\ \hline \text{Step 4} & 5 \cdot x^{2/3} \cdot y^{2 + 1/3} \\ \hline \text{Step 5} & 5 \cdot x^{2/3} \cdot y^2 \cdot y^{1/3} \\ \hline \text{Step 6} & 5y^2 \cdot x^{2/3} \cdot y^{1/3} \\ \hline \text{Step 7} & 5y^2 \cdot xy^{1/3} \\ \hline \end{array} \][/tex]
Explanation of each step:
- Step 1: Start with the given expression [tex]\(\sqrt[3]{125 x^2 y^7}\)[/tex].
- Step 2: Express the cube root in terms of rational exponents: [tex]\(125^{1/3} (x^2)^{1/3} (y^7)^{1/3}\)[/tex].
- Step 3: Simplify each term separately. [tex]\(125^{1/3} = 5\)[/tex], [tex]\((x^2)^{1/3} = x^{2/3}\)[/tex], [tex]\((y^7)^{1/3} = y^{7/3}\)[/tex].
- Step 4: Decompose [tex]\(y^{7/3}\)[/tex] into [tex]\(y^2 \cdot y^{1/3}\)[/tex] by writing [tex]\(7/3\)[/tex] as [tex]\(2 + 1/3\)[/tex].
- Step 5: Combine the terms to separate out [tex]\(y^2\)[/tex] and [tex]\(y^{1/3}\)[/tex].
- Step 6: Rewrite the combined term for clarity: [tex]\(5y^2 \cdot x^{2/3} \cdot y^{1/3}\)[/tex].
- Step 7: Re-arrange the terms, if needed, for standard form: [tex]\(5y^2 \cdot x^{2/3} \cdot y^{1/3}\)[/tex].
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.