Discover a world of knowledge at Westonci.ca, where experts and enthusiasts come together to answer your questions. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
To determine the correct simplification of the expression [tex]\(\sqrt[3]{7} = 7^{\frac{1}{3}}\)[/tex], let's examine each option:
### Option A:
[tex]\[ \left(7^{\frac{1}{3}}\right)^3 = 7^{\frac{1}{3}} \cdot 7^{\frac{1}{3}} \cdot 7^{\frac{1}{3}} = 7^{\frac{1}{3} \cdot \frac{1}{3} \cdot \frac{1}{3}} = 7^{\frac{3}{3}} = 7^1 = 7 \][/tex]
This option incorrectly simplifies the exponents. The correct multiplication for exponents should be addition, not multiplication.
### Option B:
[tex]\[ \left(7^{\frac{1}{3}}\right)^3 = 7^{\frac{1}{3}} \cdot 7^{\frac{1}{3}} \cdot 7^{\frac{1}{3}} = 7 \cdot 7^{\frac{1}{3}} = 3 \cdot \frac{1}{3} \cdot 7 = 1 \cdot 7 = 7 \][/tex]
This option contains errors in both the simplification process and the application of exponent rules.
### Option C:
[tex]\[ \left(7^{\frac{1}{3}}\right)^3 = 7^{\frac{1}{3}} \cdot 7^{\frac{1}{3}} \cdot 7^{\frac{1}{3}} = 7 \cdot\left(\frac{1}{3} + \frac{1}{3} + \frac{1}{3}\right) = 7 \cdot \frac{3}{3} = 7 \cdot 1 = 7 \][/tex]
This option makes a logical error by mixing up the base multiplication and the exponent addition in an incorrect manner.
### Option D:
[tex]\[ \left(7^{\frac{1}{3}}\right)^3 = 7^{\frac{1}{3}} \cdot 7^{\frac{1}{3}} \cdot 7^{\frac{1}{3}} = 7^{\frac{1}{3} + \frac{1}{3} + \frac{1}{3}} = 7^{\frac{3}{3}} = 7^1 = 7 \][/tex]
This option correctly applies the rule for multiplying exponents: when multiplying like bases, you add the exponents. The exponent [tex]\(\frac{1}{3} + \frac{1}{3} + \frac{1}{3}\)[/tex] simplifies to 1.
Thus, after evaluating all options, the correct simplification is:
[tex]\[ \left(7^{\frac{1}{3}}\right)^3 = 7^{\frac{1}{3}} \cdot 7^{\frac{1}{3}} \cdot 7^{\frac{1}{3}} = 7^{\frac{1}{3} + \frac{1}{3} + \frac{1}{3}} = 7^{\frac{3}{3}} = 7^1 = 7 \][/tex]
The correct answer is option D.
### Option A:
[tex]\[ \left(7^{\frac{1}{3}}\right)^3 = 7^{\frac{1}{3}} \cdot 7^{\frac{1}{3}} \cdot 7^{\frac{1}{3}} = 7^{\frac{1}{3} \cdot \frac{1}{3} \cdot \frac{1}{3}} = 7^{\frac{3}{3}} = 7^1 = 7 \][/tex]
This option incorrectly simplifies the exponents. The correct multiplication for exponents should be addition, not multiplication.
### Option B:
[tex]\[ \left(7^{\frac{1}{3}}\right)^3 = 7^{\frac{1}{3}} \cdot 7^{\frac{1}{3}} \cdot 7^{\frac{1}{3}} = 7 \cdot 7^{\frac{1}{3}} = 3 \cdot \frac{1}{3} \cdot 7 = 1 \cdot 7 = 7 \][/tex]
This option contains errors in both the simplification process and the application of exponent rules.
### Option C:
[tex]\[ \left(7^{\frac{1}{3}}\right)^3 = 7^{\frac{1}{3}} \cdot 7^{\frac{1}{3}} \cdot 7^{\frac{1}{3}} = 7 \cdot\left(\frac{1}{3} + \frac{1}{3} + \frac{1}{3}\right) = 7 \cdot \frac{3}{3} = 7 \cdot 1 = 7 \][/tex]
This option makes a logical error by mixing up the base multiplication and the exponent addition in an incorrect manner.
### Option D:
[tex]\[ \left(7^{\frac{1}{3}}\right)^3 = 7^{\frac{1}{3}} \cdot 7^{\frac{1}{3}} \cdot 7^{\frac{1}{3}} = 7^{\frac{1}{3} + \frac{1}{3} + \frac{1}{3}} = 7^{\frac{3}{3}} = 7^1 = 7 \][/tex]
This option correctly applies the rule for multiplying exponents: when multiplying like bases, you add the exponents. The exponent [tex]\(\frac{1}{3} + \frac{1}{3} + \frac{1}{3}\)[/tex] simplifies to 1.
Thus, after evaluating all options, the correct simplification is:
[tex]\[ \left(7^{\frac{1}{3}}\right)^3 = 7^{\frac{1}{3}} \cdot 7^{\frac{1}{3}} \cdot 7^{\frac{1}{3}} = 7^{\frac{1}{3} + \frac{1}{3} + \frac{1}{3}} = 7^{\frac{3}{3}} = 7^1 = 7 \][/tex]
The correct answer is option D.
We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.