Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Discover solutions to your questions from experienced professionals across multiple fields on our comprehensive Q&A platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

Use the information below to determine the probability of each event occurring. Simplify if possible.

A die with sides numbered 1 to 6 is rolled. Find the probability of rolling each outcome.

5. [tex]P(5) = \qquad[/tex]

6. [tex]P(1 \text{ or } 2) = \qquad[/tex]

7. [tex]P(\text{odd number}) = \qquad[/tex]

8. [tex]P(\text{not } 6) = \qquad[/tex]

9. [tex]P(\text{even number}) = \qquad[/tex]

10. [tex]P(1, 2, 3, \text{ or } 4) = \qquad[/tex]

Sagot :

To determine the probability of each specified event occurring when rolling a die with sides numbered 1 to 6, we need to analyze each scenario:

1. The probability of rolling a specific number (like 5):
[tex]\[ P(5) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \][/tex]
Since there is only one way to roll a 5, the probability is:
[tex]\[ P(5) = \frac{1}{6} \approx 0.1667 \][/tex]

2. The probability of rolling a 1 or a 2:
[tex]\[ P(1 \text{ or } 2) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \][/tex]
There are two favorable outcomes (rolling a 1 or a 2):
[tex]\[ P(1 \text{ or } 2) = \frac{2}{6} = \frac{1}{3} \approx 0.3333 \][/tex]

3. The probability of rolling an odd number (1, 3, 5):
[tex]\[ P(\text{odd number}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \][/tex]
There are three odd numbers on a die (1, 3, 5):
[tex]\[ P(\text{odd number}) = \frac{3}{6} = \frac{1}{2} = 0.5 \][/tex]

4. The probability of rolling a number that is not 6:
[tex]\[ P(\text{not 6}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \][/tex]
There are five favorable outcomes (1, 2, 3, 4, 5):
[tex]\[ P(\text{not 6}) = \frac{5}{6} \approx 0.8333 \][/tex]

5. The probability of rolling an even number (2, 4, 6):
[tex]\[ P(\text{even number}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \][/tex]
There are three even numbers on a die (2, 4, 6):
[tex]\[ P(\text{even number}) = \frac{3}{6} = \frac{1}{2} = 0.5 \][/tex]

6. The probability of rolling a 1, 2, 3, or 4:
[tex]\[ P(1, 2, 3, \text{ or } 4) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \][/tex]
There are four favorable outcomes (1, 2, 3, 4):
[tex]\[ P(1, 2, 3, \text{ or } 4) = \frac{4}{6} = \frac{2}{3} \approx 0.6667 \][/tex]

Summarizing the results:
1. [tex]\( P(5) \approx 0.1667 \)[/tex]
2. [tex]\( P(1 \text{ or } 2) \approx 0.3333 \)[/tex]
3. [tex]\( P(\text{odd number}) = 0.5 \)[/tex]
4. [tex]\( P(\text{not 6}) \approx 0.8333 \)[/tex]
5. [tex]\( P(\text{even number}) = 0.5 \)[/tex]
6. [tex]\( P(1, 2, 3, \text{ or } 4) \approx 0.6667 \)[/tex]
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.