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A cannon is fired. The mass of the cannon is 850 kg and the mass of the cannonball is 3 kg. After the cannon fires, the ball is shot out at a speed of 120 m/s. The cannon moves too, but in the opposite direction. What is the speed of the cannon’s recoil?

Sagot :

MathPhys

Answer:

0.42 m/s

Explanation:

Momentum is conserved before and after the cannon is fired. Momentum of an object (p) is equal to mass (m) times velocity (v) (speed and direction). Initially, both the cannon and the cannonball are at rest, so the total momentum of the system is zero. Therefore, the final momentum of the system must also be zero.

p = p₀

p = 0

m₁ v₁ + m₂ v₂ = 0

(850 kg) v₁ + (3 kg) (120 m/s) = 0

(850 kg) v₁ = -360 kg m/s

v₁ = -0.42 m/s

Rounded to two significant figures, the cannon recoils at 0.42 m/s.

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