Answered

Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Get quick and reliable answers to your questions from a dedicated community of professionals on our platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

What are the resulting coefficients when you balance the chemical equation for the combustion of ethane, [tex]C_2H_6[/tex]?

In this reaction, ethane is burned in the presence of oxygen [tex](O_2)[/tex] to form carbon dioxide [tex](CO_2)[/tex] and water [tex](H_2O)[/tex].

[tex]\[ C_2H_6(g) + \ldots O_2(g) \rightarrow \ldots CO_2(g) + \ldots H_2O(g) \][/tex]

Recall that the coefficients of the final balanced equation should be whole numbers. Thus, you might need to multiply through the equation by a factor of two to obtain whole numbers in your last step.

Express the coefficients as integers separated by commas.

Sagot :

GinnyAnswer
To balance the chemical equation for the combustion of ethane ([tex]\(C_2H_6\)[/tex]), we need to ensure that there are the same number of each type of atom on both the reactant and product sides of the equation.

1. Write down the unbalanced equation:
[tex]\[ C_2H_6 + O_2 \rightarrow CO_2 + H_2O \][/tex]

2. Balance carbon (C) atoms:
There are 2 carbon atoms in [tex]\(C_2H_6\)[/tex]. Therefore, we need 2 molecules of [tex]\(CO_2\)[/tex] to balance the carbon atoms:
[tex]\[ C_2H_6 + O_2 \rightarrow 2CO_2 + H_2O \][/tex]

3. Balance hydrogen (H) atoms:
There are 6 hydrogen atoms in [tex]\(C_2H_6\)[/tex]. Thus, we need 3 molecules of [tex]\(H_2O\)[/tex] to balance the hydrogen atoms:
[tex]\[ C_2H_6 + O_2 \rightarrow 2CO_2 + 3H_2O \][/tex]

4. Balance oxygen (O) atoms:
On the product side, we have a total of [tex]\(4\)[/tex] oxygen atoms from [tex]\(2CO_2\)[/tex] (since each [tex]\(CO_2\)[/tex] molecule has 2 oxygen atoms) and [tex]\(3\)[/tex] more oxygen atoms from [tex]\(3H_2O\)[/tex] (since each [tex]\(H_2O\)[/tex] molecule has 1 oxygen atom). That makes a total of [tex]\(4 + 3 = 7\)[/tex] oxygen atoms on the product side.

To balance the oxygen atoms on the reactant side, we need [tex]\(7/2\)[/tex] molecules of [tex]\(O_2\)[/tex] (since each molecule of [tex]\(O_2\)[/tex] contains 2 oxygen atoms):
[tex]\[ C_2H_6 + \frac{7}{2}O_2 \rightarrow 2CO_2 + 3H_2O \][/tex]

5. Convert to whole numbers:
The coefficients must be whole numbers. To get rid of the fraction, multiply all coefficients by 2:
[tex]\[ 2C_2H_6 + 7O_2 \rightarrow 4CO_2 + 6H_2O \][/tex]

Now, the chemical equation is balanced, and the coefficients are:
[tex]\[ 2, 7, 4, 6 \][/tex]

These coefficients represent the stoichiometric amounts of each substance involved in the balanced combustion reaction of ethane.

So, the coefficients are as follows:
2, 7, 4, 6
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.