Answered

Discover the answers you need at Westonci.ca, where experts provide clear and concise information on various topics. Join our platform to connect with experts ready to provide detailed answers to your questions in various areas. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

4. How many grams of copper (II) fluoride, CuF₂ (MW: 101.53), are needed to make 3.75 liters of a 2.4 M solution?

Sagot :

GinnyAnswer
To find out how many grams of copper (II) fluoride (CuF2) are needed to prepare 3.75 liters of a 2.4 M solution, follow these steps:

1. Understand the given values:
- Volume of the solution = 3.75 liters
- Molarity (concentration) of the solution = 2.4 M (which is 2.4 moles/liter)
- Molar mass of CuF2 = 101.53 g/mol

2. Calculate the number of moles of CuF2 required:
- Moles of solute (CuF2) = Molarity × Volume of the solution
- Moles of CuF2 = 2.4 M × 3.75 L
- Moles of CuF2 = 9.0 moles

3. Convert moles of CuF2 to grams:
- Grams of CuF2 = Moles of CuF2 × Molar mass of CuF2
- Grams of CuF2 = 9.0 moles × 101.53 g/mol
- Grams of CuF2 = 913.77 grams

Therefore, you would need 913.77 grams of copper (II) fluoride (CuF2) to make 3.75 liters of a 2.4 M solution.
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.