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Sagot :
To find the value of the fourth term in a geometric sequence where the first term [tex]\( a_1 = 15 \)[/tex] and the common ratio [tex]\( r = \frac{1}{3} \)[/tex], we can use the formula for the [tex]\( n \)[/tex]-th term of a geometric sequence:
[tex]\[ a_n = a_1 \cdot r^{n-1} \][/tex]
For the fourth term ([tex]\( n = 4 \)[/tex]):
[tex]\[ a_4 = a_1 \cdot r^{4-1} = a_1 \cdot r^3 \][/tex]
Given [tex]\( a_1 = 15 \)[/tex] and [tex]\( r = \frac{1}{3} \)[/tex], we substitute these values into the formula:
[tex]\[ a_4 = 15 \cdot \left( \frac{1}{3} \right)^3 \][/tex]
Next, calculate [tex]\( \left( \frac{1}{3} \right)^3 \)[/tex]:
[tex]\[ \left( \frac{1}{3} \right)^3 = \frac{1}{3} \cdot \frac{1}{3} \cdot \frac{1}{3} = \frac{1}{27} \][/tex]
Now multiply this result by the first term:
[tex]\[ a_4 = 15 \cdot \frac{1}{27} \][/tex]
To simplify the multiplication:
[tex]\[ 15 \cdot \frac{1}{27} = \frac{15}{27} = \frac{5}{9} \][/tex]
Therefore, the fourth term expressed as a fraction is:
[tex]\[ \boxed{\frac{5}{9}} \][/tex]
[tex]\[ a_n = a_1 \cdot r^{n-1} \][/tex]
For the fourth term ([tex]\( n = 4 \)[/tex]):
[tex]\[ a_4 = a_1 \cdot r^{4-1} = a_1 \cdot r^3 \][/tex]
Given [tex]\( a_1 = 15 \)[/tex] and [tex]\( r = \frac{1}{3} \)[/tex], we substitute these values into the formula:
[tex]\[ a_4 = 15 \cdot \left( \frac{1}{3} \right)^3 \][/tex]
Next, calculate [tex]\( \left( \frac{1}{3} \right)^3 \)[/tex]:
[tex]\[ \left( \frac{1}{3} \right)^3 = \frac{1}{3} \cdot \frac{1}{3} \cdot \frac{1}{3} = \frac{1}{27} \][/tex]
Now multiply this result by the first term:
[tex]\[ a_4 = 15 \cdot \frac{1}{27} \][/tex]
To simplify the multiplication:
[tex]\[ 15 \cdot \frac{1}{27} = \frac{15}{27} = \frac{5}{9} \][/tex]
Therefore, the fourth term expressed as a fraction is:
[tex]\[ \boxed{\frac{5}{9}} \][/tex]
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