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The sum of two numbers is 140. One number is 68 more than the other. Find the numbers.

The larger number is _______.

The smaller number is _______.

Sagot :

To solve the problem of finding two numbers given their sum and the difference between them, follow these detailed steps:

1. Let’s Define the Variables:
- Let [tex]\( x \)[/tex] be the smaller number.
- Since one number is 68 more than the other, the larger number will be [tex]\( x + 68 \)[/tex].

2. Set Up the Equation:
- According to the problem, the sum of the two numbers is 140.
- This can be written as:
[tex]\[ x + (x + 68) = 140 \][/tex]
3. Simplify the Equation:
- Combine like terms:
[tex]\[ 2x + 68 = 140 \][/tex]

4. Solve for [tex]\( x \)[/tex]:
- First, isolate the term with [tex]\( x \)[/tex] by subtracting 68 from both sides of the equation:
[tex]\[ 2x = 140 - 68 \][/tex]
- Simplify the right side:
[tex]\[ 2x = 72 \][/tex]
- Now, divide both sides by 2 to solve for [tex]\( x \)[/tex]:
[tex]\[ x = \frac{72}{2} = 36 \][/tex]

5. Find the Larger Number:
- The larger number is 68 more than the smaller number.
- So, the larger number is:
[tex]\[ 36 + 68 = 104 \][/tex]

Thus, the smaller number is 36 and the larger number is 104.

- The larger number is 104.
- The smaller number is 36.