At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Explore our Q&A platform to find reliable answers from a wide range of experts in different fields. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
To determine how many moles are contained in a certain number of grams of aspartame, you can use the formula:
[tex]\[ \text{Moles} = \frac{\text{Mass (g)}}{\text{Molar Mass} (g/mol)} \][/tex]
Given the molar mass of aspartame is 294.30 g/mol, let’s calculate the number of moles for each given mass of aspartame:
1. For 5.0 grams of aspartame:
[tex]\[ \text{Moles} = \frac{5.0 \text{ g}}{294.30 \text{ g/mol}} \][/tex]
[tex]\[ \approx 0.017 \text{ moles} \][/tex]
(rounded to three significant figures)
2. For 10.0 grams of aspartame:
[tex]\[ \text{Moles} = \frac{10.0 \text{ g}}{294.30 \text{ g/mol}} \][/tex]
[tex]\[ \approx 0.034 \text{ moles} \][/tex]
(rounded to three significant figures)
3. For 15.0 grams of aspartame:
[tex]\[ \text{Moles} = \frac{15.0 \text{ g}}{294.30 \text{ g/mol}} \][/tex]
[tex]\[ \approx 0.051 \text{ moles} \][/tex]
(rounded to three significant figures)
4. For 20.0 grams of aspartame:
[tex]\[ \text{Moles} = \frac{20.0 \text{ g}}{294.30 \text{ g/mol}} \][/tex]
[tex]\[ \approx 0.068 \text{ moles} \][/tex]
(rounded to three significant figures)
5. For 25.0 grams of aspartame:
[tex]\[ \text{Moles} = \frac{25.0 \text{ g}}{294.30 \text{ g/mol}} \][/tex]
[tex]\[ \approx 0.085 \text{ moles} \][/tex]
(rounded to three significant figures)
So, the calculated number of moles for each respective mass of aspartame are:
[tex]\[ 5.0 \text{ g} \rightarrow 0.017 \text{ moles} \][/tex]
[tex]\[ 10.0 \text{ g} \rightarrow 0.034 \text{ moles} \][/tex]
[tex]\[ 15.0 \text{ g} \rightarrow 0.051 \text{ moles} \][/tex]
[tex]\[ 20.0 \text{ g} \rightarrow 0.068 \text{ moles} \][/tex]
[tex]\[ 25.0 \text{ g} \rightarrow 0.085 \text{ moles} \][/tex]
[tex]\[ \text{Moles} = \frac{\text{Mass (g)}}{\text{Molar Mass} (g/mol)} \][/tex]
Given the molar mass of aspartame is 294.30 g/mol, let’s calculate the number of moles for each given mass of aspartame:
1. For 5.0 grams of aspartame:
[tex]\[ \text{Moles} = \frac{5.0 \text{ g}}{294.30 \text{ g/mol}} \][/tex]
[tex]\[ \approx 0.017 \text{ moles} \][/tex]
(rounded to three significant figures)
2. For 10.0 grams of aspartame:
[tex]\[ \text{Moles} = \frac{10.0 \text{ g}}{294.30 \text{ g/mol}} \][/tex]
[tex]\[ \approx 0.034 \text{ moles} \][/tex]
(rounded to three significant figures)
3. For 15.0 grams of aspartame:
[tex]\[ \text{Moles} = \frac{15.0 \text{ g}}{294.30 \text{ g/mol}} \][/tex]
[tex]\[ \approx 0.051 \text{ moles} \][/tex]
(rounded to three significant figures)
4. For 20.0 grams of aspartame:
[tex]\[ \text{Moles} = \frac{20.0 \text{ g}}{294.30 \text{ g/mol}} \][/tex]
[tex]\[ \approx 0.068 \text{ moles} \][/tex]
(rounded to three significant figures)
5. For 25.0 grams of aspartame:
[tex]\[ \text{Moles} = \frac{25.0 \text{ g}}{294.30 \text{ g/mol}} \][/tex]
[tex]\[ \approx 0.085 \text{ moles} \][/tex]
(rounded to three significant figures)
So, the calculated number of moles for each respective mass of aspartame are:
[tex]\[ 5.0 \text{ g} \rightarrow 0.017 \text{ moles} \][/tex]
[tex]\[ 10.0 \text{ g} \rightarrow 0.034 \text{ moles} \][/tex]
[tex]\[ 15.0 \text{ g} \rightarrow 0.051 \text{ moles} \][/tex]
[tex]\[ 20.0 \text{ g} \rightarrow 0.068 \text{ moles} \][/tex]
[tex]\[ 25.0 \text{ g} \rightarrow 0.085 \text{ moles} \][/tex]
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.