Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Explore our Q&A platform to find in-depth answers from a wide range of experts in different fields. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

Soccer balls go on sale for [tex]\$7.50[/tex] each. The store also sells footballs, and the manager wants to earn a daily profit of [tex]\$400[/tex] from both items. The equation [tex]y = -4x^2 + 80x - 150[/tex] models the store's daily profit, [tex]y[/tex], for selling footballs at [tex]x[/tex] dollars. Explain how to find the price per football needed to meet the goal.

Sagot :

To determine the price per football needed to achieve a daily profit of \[tex]$400, we'll follow these steps: ### Step-by-Step Solution 1. Understand the given equation and context: - The profit equation is \( y = -4x^2 + 80x - 150 \), where \( y \) represents the profit and \( x \) is the price per football in dollars. - The manager wants to earn a daily profit of \$[/tex]400.

2. Set up the equation with the desired profit:
- Substitute [tex]\( y \)[/tex] with the desired profit of \[tex]$400 in the equation: \[ 400 = -4x^2 + 80x - 150 \] 3. Form a standard quadratic equation: - Rearrange the equation to the standard quadratic form: \[ -4x^2 + 80x - 150 - 400 = 0 \] \[ -4x^2 + 80x - 550 = 0 \] 4. Simplify the quadratic equation: - To make calculations easier, divide the entire equation by -2 (or any common factor, if desired): \[ 2x^2 - 40x + 275 = 0 \] 5. Solve the quadratic equation: - For a quadratic equation of the form \( ax^2 + bx + c = 0 \), use the quadratic formula \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \). - Here, \( a = 2 \), \( b = -40 \), and \( c = 275 \). Plug these values into the quadratic formula: \[ x = \frac{-(-40) \pm \sqrt{(-40)^2 - 4 \cdot 2 \cdot 275}}{2 \cdot 2} \] \[ x = \frac{40 \pm \sqrt{1600 - 2200}}{4} \] \[ x = \frac{40 \pm \sqrt{-600}}{4} \] 6. Solve the discriminant (b² - 4ac): - The discriminant is \( \sqrt{-600} \), which can be expressed as \( \sqrt{600}i \) where \( i \) is the imaginary unit ( \( i = \sqrt{-1} \)). \[ x = \frac{40 \pm 10\sqrt{6}i}{4} \] \[ x = 10 \pm \frac{5\sqrt{6}i}{2} \] ### Conclusion To meet the daily profit goal of \$[/tex]400, the price per football must be:
- [tex]\( x = 10 - \frac{5\sqrt{6}i}{2} \)[/tex]
- [tex]\( x = 10 + \frac{5\sqrt{6}i}{2} \)[/tex]

These solutions indicate complex numbers, suggesting that within the real-number system, there are no real prices [tex]\( x \)[/tex] that will exactly yield a profit of \$400 given by the profit model. However, these complex numbers show the mathematical consistency with the quadratic equation provided.
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.