Answered

Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Get immediate answers to your questions from a wide network of experienced professionals on our Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

What is the point-slope form of a line with slope [tex]\(-3\)[/tex] that contains the point [tex]\((10, -1)\)[/tex]?

A. [tex]\(x+1=-3(y-10)\)[/tex]
B. [tex]\(y+1=3(x-10)\)[/tex]
C. [tex]\(y+1=3(x+10)\)[/tex]
D. [tex]\(y+1=-3(x-10)\)[/tex]

Sagot :

GinnyAnswer
To determine the point-slope form of a line with a given slope and point, we use the point-slope formula:

[tex]\[ y - y_1 = m(x - x_1) \][/tex]

where [tex]\( (x_1, y_1) \)[/tex] is a point on the line and [tex]\( m \)[/tex] is the slope.

Given:
- Slope ([tex]\( m \)[/tex]) = -3
- Point ([tex]\( x_1, y_1 \)[/tex]) = (10, -1)

Plug these values into the point-slope formula:

[tex]\[ y - (-1) = -3(x - 10) \][/tex]

Simplify the equation:

[tex]\[ y + 1 = -3(x - 10) \][/tex]

Hence, the point-slope form of the line is:

[tex]\[ y + 1 = -3(x - 10) \][/tex]

So, the correct answer is:

D. [tex]\( y + 1 = -3(x - 10) \)[/tex]
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.